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Mathematics 31 Online
nolegirl24:

Find the average rate of change from x = 3 to x = 15 for the function f(x) = 0.01(2)x and select the correct answer below. 0.08 12 27.3 327.68

nolegirl24:

Im not good at this :(:(

Vocaloid:

|dw:1508782428475:dw|

Vocaloid:

^this formula looks scary but we can break it down

nolegirl24:

OKay please

Vocaloid:

the formula tells you the average rate of change from "x" to "a" where we can replace x and a with the numbers from our problem

nolegirl24:

ok

Vocaloid:

here is our original problem: "average rate of change from x = 3 to x = 15 for the function f(x) = 0.01(2)x" in this case, "x" would be 15 and "a" would be 3

Vocaloid:

|dw:1508782527428:dw|

nolegirl24:

15 - 3 = 12

Vocaloid:

so you would start by finding the value of the function at x = 3 and x = 15 so if f(x) = 0.01(2)^x, then what is f(x) when x = 3?

nolegirl24:

I just got brain washed and now im confused. (Not Literally) but yes im confised

Vocaloid:

x = 3 means we can replace "x" with "3" whenever x shows up f(x) = 0.01(2)^x replace "x" with 3 to get f(3) = 0.01(2)^3 = ?

nolegirl24:

Oh okay hold on. Im sorry i just dont get it most of the time

nolegirl24:

0.8???

nolegirl24:

@Vocaloid

Vocaloid:

0.08, be careful with decimal places

Vocaloid:

now do the same thing for x = 15

Vocaloid:

f(15) = 0.01(2)^15 = ?

nolegirl24:

I have to do that 15 times :o

Vocaloid:

you can use a calculator

Vocaloid:

wolframalpha.com type in 0.01(2)^15

nolegirl24:

327.68

Vocaloid:

awesome! now we just plug that into our formula

Vocaloid:

|dw:1508783090124:dw|

nolegirl24:

Okay..

Vocaloid:

(327.68-0.08)/12 = 27.3 (C)

nolegirl24:

27.3????

Vocaloid:

yup

nolegirl24:

Thanks!

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