Question

http://prntscr.com/h14e6o

Answer 1

@563blackghost im so glad ur on please help me with this one math problem :)

Answer 2

@563blackghost please just try your very best to answer this question :)

Answer 3

What did I send you again? I forgot the equation I made.

Answer 4

y=x+6.

Answer 5

Looks great!

Answer 6

ok thanks

Answer 7

ok i already answered these questions but i need you to check and makes sure they are correct

Answer 8

Looks great!

Answer 9

Sam is observing the velocity of a car at different times. After three hours, the velocity of the car is 51 km/h. After five hours, the velocity of the car is 59 km/h.

Part A: Write an equation in two variables in the standard form that can be used to describe the velocity of the car at different times. Show your work and define the variables used. (5 points)

Part B: How can you graph the equation obtained in Part A for the first six hours? (5 points)

Answer 10

answer:
Part A:
y - 51 = 59 - 51 / 5 - 3 (x-3)
y - 51 = 4 (x-3)
y = 4x -12 + 51
y= 4x + 39
where x is the time and y is the velocity of car at any time x.

Part B:
y =4 * 6 + 39 = 24 + 39 = 63 ~km/h

Answer 11

It's great, BUT you need to change it to standard form for A (it's in slope-intercept form).

Answer 12

OH OK .... how do i do that? please fix it

Answer 13

We we need x and y on the same side so...

\(\large\bf{y=4x+39}\)

\(\large\bf{4x-y=-39}\)

Answer 14

oh ok got it!

Answer 15

great!