What are the domain and range of each relation? Drag the answer into the box to match each relation. https://static.k12.com/nextgen_media/assets/8075071-NG_AL1_SemA_04_UT_19.png < > __________________ https://static.k12.com/nextgen_media/assets/8075072-NG_AL1_SemA_04_UT_20.png < > _____________ Domain: {-3, -2, 0, 2} Range: {0, 1} Domain: {-2, 0, 2, 4} Range: {-3, - 1, 0} Domain: {-3, -1, 0, 3} Range: {-1, 0, 1, 2, 3}
@Vocaloid
for a (the thing with the blue ovals) your domain would just be all the x-values and all the y-values since all of them are included with the arrows
A. the second part B. the third part
i figured it out
yeah those answers are right, gj
ok
Which relations are functions? Select Function or Not a function for each graph. https://static.k12.com/nextgen_media/assets/8076063-NG_AL1_SemA_04_UT_11.png Function or Not a Function https://static.k12.com/nextgen_media/assets/8076062-NG_AL1_SemA_04_UT_10.png Function or Not a Function https://static.k12.com/nextgen_media/assets/8076064-NG_AL1_SemA_04_UT_12.png Function or Not a Function https://static.k12.com/nextgen_media/assets/8076061-NG_AL1_SemA_04_UT_09.png Function or Not a Function
do the vertical line test if you can draw a vertical line that crosses more than 2 points on the graph, then it is not a function
let me know what you get for each graph
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1. Not a function 2. function 3. non a function 4. function
am i correct ?
awesome, that's it
really ?
yes
how ?
that's the right answer, I'm not sure what you mean
it's ok
don't worry about it
https://static.k12.com/nextgen_media/assets/8076065-NG_AL1_SemA_04_UT_15.png The function f(x) is graphed on the coordinate plane. What is f(−4) ? Enter your answer in the box. f(−4) = __________
put your finger on x = -4 go straight up until you touch the graph then go straight to the right until you touch the y-axis what y-value do you get?
8
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4
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good, 4
so 4 is your answer
The graph shows the profit, y, of a community fundraiser, with respect to the number of tickets sold, x. Use the graph to complete each statement. Drag and drop the answers into the boxes. The y-intercept is ___________ . The y-intercept represents ___________ 20, 35, the profit per ticket, the initial amount of expenses, the number of tickets sold, or -700
i forgot
hint: the y-intercept is the value of y when x = 0
when x = 0, what is the value of the graph?
x value
what is y equal when x equals 0?
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-700
i was trying to say 0 but i thought wrong
good, -700
but the computer wasn't acting right
if x = 0 that means no tickets were sold, so these must be the initial costs
that's it for your problem
so the y-intercept is the initial ampount
yes, they're the initial expenses
the y-intercept represents ?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid yes, they're the initial expenses \(\color{#0cbb34}{\text{End of Quote}}\)
no i meant by look back at the question
I am.
I have stated the y-intercept represents the initial expenses.
but it's one
just pick one
you can't have both
on each question
here are your answer choices: 20, 35, the profit per ticket, the initial amount of expenses, the number of tickets sold, or -700 we have stated the y-intercept is -700 and this represents the initial expenses.
pick the two answer choices that match what I said.
oh i see
Graph f(x)=|x−2|+3 .
start with f(x) = |x| and apply the appropriate transformations
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that;s what i did
^ start with this graph f(x) = |x| then we translate 2 units to the right and 3 units up
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the one that i did was right or wrong ?
the one you did was not correct
please see what I have written
your graph should look like a V
is this correct ?
please see what I have drawn
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like that one ?
yes
i kinda like can't do it on mine
draw a point at (2,3) and make a V-shaped graph
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the slope on the right-side should be 1 and the slope on the left-side should be -1
like this ?
yupp good
or like this
which one ?
uh they both look the same to me but the first one i guess?
you think ?
first one is correct
ok last one
Graph the function f(x)=−1/4x−2.
start with the point (0,-2)
this correct ?
hint: try finding the x-intercept by setting f(x) = 0
if 0 = (−1/4)x−2 then x = ?
-8
awesome job! so your graph should connect (-8,0) and (0,-2) which means you need to adjust your original graph
is this it ?
yupp good can we close this an open a new question please ^^"
yes ma'am
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