Helpp please
Ill help you in just a sec is that ok :D?
Ok what do you need help with?
=)
Ok well lets first solve for X and Y. What i like to do (might seem stupid) but plug in some numbers and go from there.
Ugh I'm confused
Ok so jsut find out what the value of x and y is and then we can narrow down the value of q
x=3y+4
\[y=\frac{ x }{ 3 }-\frac{ 4 }{ 3 }\]
ok good so using those formulas what is the value of x and y....what does x equal and what does y equal
y=-4/3?
I would assume yes.
okay and now?
Well now once you know the product of y and x plug it into the second equation and you can find the value of q
I got Q4+Q4-6y=8
Sounds like you know what your doing!
@zarkam21 If the solution is a line (as stated in the original problem) then both of the equations must be equivalent
you have x - 3y = 4 Qx -6y = 8 How can we make equations 1 and 2 equal?
we add them together?
@Vocaloid
If we add them together we don't have two equations anymore Start by multiplying equation 1 by 2
Qx^2-18=32
Equation one not equation 2
x -3y = 4 Multiply this by 2
2x-6y=8
Good nowhere compare the two equations 2x -6y = 8 Qx -6y =8
*now
Oh 2?
Good Q = 2
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