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Mathematics 21 Online
zarkam21:

Helpp please

SourMunchkin7806:

Ill help you in just a sec is that ok :D?

SourMunchkin7806:

Ok what do you need help with?

zarkam21:

1 attachment
zarkam21:

=)

SourMunchkin7806:

Ok well lets first solve for X and Y. What i like to do (might seem stupid) but plug in some numbers and go from there.

zarkam21:

Ugh I'm confused

SourMunchkin7806:

Ok so jsut find out what the value of x and y is and then we can narrow down the value of q

zarkam21:

x=3y+4

zarkam21:

\[y=\frac{ x }{ 3 }-\frac{ 4 }{ 3 }\]

SourMunchkin7806:

ok good so using those formulas what is the value of x and y....what does x equal and what does y equal

zarkam21:

y=-4/3?

SourMunchkin7806:

I would assume yes.

zarkam21:

okay and now?

SourMunchkin7806:

Well now once you know the product of y and x plug it into the second equation and you can find the value of q

zarkam21:

I got Q4+Q4-6y=8

SourMunchkin7806:

Sounds like you know what your doing!

Vocaloid:

@zarkam21 If the solution is a line (as stated in the original problem) then both of the equations must be equivalent

Vocaloid:

you have x - 3y = 4 Qx -6y = 8 How can we make equations 1 and 2 equal?

zarkam21:

we add them together?

zarkam21:

@Vocaloid

Vocaloid:

If we add them together we don't have two equations anymore Start by multiplying equation 1 by 2

zarkam21:

Qx^2-18=32

Vocaloid:

Equation one not equation 2

Vocaloid:

x -3y = 4 Multiply this by 2

zarkam21:

2x-6y=8

Vocaloid:

Good nowhere compare the two equations 2x -6y = 8 Qx -6y =8

Vocaloid:

*now

zarkam21:

Oh 2?

Vocaloid:

Good Q = 2

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