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Mathematics 13 Online
kaylak:

https://assets.questioncove.com/attachments/1509472947-59f8b1dc2d86127c720cc000-Capture.PNG anyone know thgis

kaylak:

@Vocaloid

kaylak:

can you give me something i don't want to pay for a tutor

Vocaloid:

try graphing them and then use the graph to determine where the functions are equal, where f>g and where g>f

kaylak:

i already do for mcro

kaylak:

help?

Vocaloid:

again, try using a website to create a graph of each function and follow my suggested instructions

kaylak:

1x f is larger

Vocaloid:

http://www.wolframalpha.com/input/?i=log7(x)+vs+log4(x)

kaylak:

i'm calculating lol

kaylak:

am i correct though

kaylak:

i just can't figure out the = one

Vocaloid:

there are regions of the graph where f is bigger, regions of the graph where g is bigger, and one x-value where they are equal

Vocaloid:

hint: log(1) = 0

kaylak:

so there is more than one value for f>g

Vocaloid:

the region should be expressed in interval notation

kaylak:

so i would find the interval of f g etc.?

Vocaloid:

1. find the interval of x where f > g 2. find the interval of x where g > f 3. find the x-value where f = g three tasks

kaylak:

it won't solve in mathway how would i do it on my own

Vocaloid:

this one is actually pretty difficult to solve by hand

Vocaloid:

Vocaloid:

[just consider the values where x > 0 idk why both sides are graphed]

Vocaloid:

blue is f and purple is g

sillybilly123:

how's bout a Base-Shift, Voc, like "Metamorphmagus" but different, maybe "Logmetamorphmagus" So: \(f = log_7 x = \dfrac{log_n x}{log_n 7} \) \(g = log_4 x = \dfrac{log_n x}{log_n 4} \) \(f = g \implies \dfrac{log_n x}{log_n 7} = \dfrac{log_n x}{log_n 4}\) only the null solution works there for equality that's a start .... and highly highly recommend Desmos for scoping stuff out if you are struggling to see shapes. https://www.desmos.com/calculator/zijf2ff9su for which one is bigger, it should be obvious to the right of the null solution and in fact to the left too......as it's all now going mental on that side but the graphing thing .....

Vocaloid:

thanks silly, I couldn't remember for the life of me how to do that ^^

kaylak:

it appears equal at -2

Vocaloid:

remember we are only considering the positive x values

Vocaloid:

where do the purple and blue lines intersect?

Vocaloid:

on the x-axis that is?

kaylak:

at 1 hey i was right the first time

Vocaloid:

good that's your x value for f = g

kaylak:

it appears that 2 is g

Vocaloid:

we are looking for a range of x values where g > f your answer should be something like "g > f for x values from ___ to ____"

kaylak:

so -2 to 2

kaylak:

but blue isn't bigger anywhere on the graph?

Vocaloid:

we are only considering positive x values

Vocaloid:

examine the graph carefully

kaylak:

blue is larger at 0.5

kaylak:

red 1.5 to 2 ?

Vocaloid:

getting closer but not quite

Vocaloid:

remember the graph starts at x = 0 and extends to x = infinity

Vocaloid:

x = 1 should be the "cutoff" point where purple starts to be greater than blue

kaylak:

oh so 1.5 to infinity

kaylak:

?

Vocaloid:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid x = 1 should be the "cutoff" point where purple starts to be greater than blue \(\color{#0cbb34}{\text{End of Quote}}\)

kaylak:

so 1 to infinity

Vocaloid:

good

kaylak:

for both or just g

kaylak:

what is f

Vocaloid:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid blue is f and purple is g \(\color{#0cbb34}{\text{End of Quote}}\)

kaylak:

but are both 1 to infinity

Vocaloid:

we have determined that g > f from 1 to infinity now determine where f > g.

kaylak:

do we still think positive or no

Vocaloid:

yes.

kaylak:

0.5 to inifinity?

kaylak:

am i right

Vocaloid:

|dw:1509481057157:dw|

Vocaloid:

|dw:1509481062947:dw|

Vocaloid:

fill in the blanks: "f > g from x = __ to x = __"

kaylak:

so 0 and 1

Vocaloid:

good

kaylak:

ok

kaylak:

thank you

Vocaloid:

now put everything together to get your final answer

kaylak:

so basically just explain

Vocaloid:

yes

kaylak:

omg thank you

kaylak:

made a 100 on multiple chocie

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