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Antiderivative of (a)cos(ax) = sin(ax) Walk me through the steps here...
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\[\int\limits_{}^{}acos(x)dx = a \int\limits_{}^{}\cos(x)dx = a \sin(x)\] I thought it was like this.
you're forgetting the a within your cos expression, it's acos(ax) not acos(x)
anyway you would apply the opposite of the chain rule (I think that's what it's called) to find the integral
brb
Oh right...chain rule...
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Still getting used to reversing derivatives.
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