If 2003-08-03-00-00_files/i0250000.jpg and 2003-08-03-00-00_files/i0250001.jpg, evaluate 2003-08-03-00-00_files/i0250002.jpg for x = –1. A. 3 B. 2003-08-03-00-00_files/i0250003.jpg C. 2003-08-03-00-00_files/i0250004.jpg D. –3
o.o Uh...Try copy and paste the image
if f(x)=1/2x^2-3 and g(x)=3x/4, evaluate F(x) divided by G(x) for x=-1
nope
@Vocaloid
f(x)/g(x) is simply (1/(2x^2-3)) / (3x/4) evaluate this when x = -1
|dw:1510536035673:dw|
yup
@Vocaloid
the original notation is a bit unclear, could you take a screenshot or use the equation tool to write the original functions?
ok
is it 1/2x^2 - 3 or 1/(2x^2 -3) or something else?
the first
fractions
ok, so what do you get when you substitute x = -1 into 1/2x^2 - 3?
2? idk
replace "x" with "-1" and evaluate 1/2x^2 - 3
-5?
1/-5
(1/2)(-1)^2 - 3 = ?
|dw:1510536596734:dw|
2(-1)^2 - 3 is not -5
-1
good, so now let's evaluate g(-1)
g(-1)=3x/4 = 3(-1)/4 = ?
|dw:1510536743711:dw|
good, so now let's divide (1/-1) / (-3/4) = ?
how do you divide fractions?
switch the numerator and denominator of the second fraction
then change the division sign to a multiplication sign
(1/-1) / (-3/4) = -1 * (4/-3) = ?
-4/3?
almost, make sure to cancel out the - signs
it ends up being 4/3 (is that one of the answer choices?)
or is 1 1/3 an answer choice? (it's 4/3 as a mixed number)
yess!! thank you!
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