Ask your own question, for FREE!
Mathematics 9 Online
mikewwe13:

https://static.k12.com/nextgen_media/assets/8078626-NG_AL1_J_06_U06_Quiz_03.png The graph shows the function g(x) . Select from the drop-down menu to correctly compare ​ g(x) ​ and f(x)=−3(x+1) . The y-intercept of ​ f(x) ​ is _____________ the y-intercept of ​ g(x) ​ . less than greater than equal to

mikewwe13:

@Vocaloid

Vocaloid:

I have answered this already, set x = 0 and calculate the y-intercept of f(x)

mikewwe13:

sorry i've been gone the time you've been answering me

mikewwe13:

and it's less than

Vocaloid:

good.

mikewwe13:

it's less than ?

Vocaloid:

yes.

mikewwe13:

could you help me if you're not busy ?

mikewwe13:

with more please with everything

Vocaloid:

sure

mikewwe13:

you're not busy with college or anything ?

mikewwe13:

today

Vocaloid:

I'm not busy right now

mikewwe13:

ok

mikewwe13:

The table shows the function ​ g(x) ​ . Select from the drop-down menu to correctly compare the growth factors for the exponential functions g(x) and f(x)=4(3)x . The growth factor of​ f(x) ​is __________________ the growth factor of g(x) . less than greater than equal to

mikewwe13:

i'll send the pic

mikewwe13:

1 attachment
mikewwe13:

f(x) = 4(3)^x

Vocaloid:

if you look at the table of g(x) each value is being multiplied by 4 to get to the next value making 4 the growth factor of g

Vocaloid:

if you look at f(x) each number is being multiplied by 3 (the number with the exponent x) making 3 the growth factor of f

mikewwe13:

equal to

Vocaloid:

please review what I have said carefully

mikewwe13:

oh wait no

mikewwe13:

it's greater than

Vocaloid:

the growth factor of f(x) is 3 the growth factor of g(x) is 4 therefore the growth factor of f(x) is ______ than g(x) fill in the blank

mikewwe13:

less than

Vocaloid:

good, that's it.

mikewwe13:

https://static.k12.com/nextgen_media/assets/8078601-NG_AL1_J_06_U06_Quiz_08.png One day, Fiona and Heidi each bought coins at a coin shop. The equation f(x) = 3x + 12 represents the value of Fiona’s coin, in dollars, x years later. The graph shows the value of Heidi’s coin, in dollars, x years later. Select from the drop-down menus to complete the statement. When they bought their coins, ( Fiona's or Heidi's ) coin was worth ( $3, $6, $9, or $12 ) more than ( Fiona's or Heidi's ) coin.

Vocaloid:

hint: calculate f(x) at year 0 (when x = 0)

mikewwe13:

f(0) = 0

Vocaloid:

re-read the problem please

Vocaloid:

f(x) = 3x + 12 calculate f(x) when x = 0.

mikewwe13:

-4

Vocaloid:

replace "x" with "0" and calculate f(x).

mikewwe13:

f(0)

Vocaloid:

now calculate f(0).

mikewwe13:

f(0) = 0

Vocaloid:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid f(x) = 3x + 12 calculate f(x) when x = 0. \(\color{#0cbb34}{\text{End of Quote}}\)

Vocaloid:

copy down the original function replace "x" with 0 then calculate what the function is equal to.

mikewwe13:

f(x) f(0) like this ?

Vocaloid:

write this down: "f(x) = 3x + 12" replace the "x" with "0" whenever x shows up then calculate the function.

mikewwe13:

"f(x) = 3x + 12" = 12

Vocaloid:

good, f(0) = 12

Vocaloid:

now use the graph to find h(0).

mikewwe13:

so it's $12 right first ?

Vocaloid:

it is not $12 it is asking for the difference between heidi's coin and fiona's coin so we must subtract f(0) - h(0).

Vocaloid:

use the graph to find the value of heidi's coin at year 0

mikewwe13:

f(0) - h(0). = 0

Vocaloid:

again, use the graph to find the value of h(x) at x = 0.

mikewwe13:

ok i found it

Vocaloid:

what did you get as the value?

mikewwe13:

-10

mikewwe13:

correct me

Vocaloid:

-10 is not a value anywhere on the graph

Vocaloid:

put your finger on x = 0 then go up until you touch the graph what value do you get for h(x)?

mikewwe13:

6

Vocaloid:

good, that's h(0)

Vocaloid:

so if f(0) = 12 and h(0) = 6 f(0) - h(0) = ?

mikewwe13:

f6

Vocaloid:

just 6 but good

mikewwe13:

6 right

Vocaloid:

so fiona's coin is worth more than heidi's coin by $6

mikewwe13:

Compounds A and B are used in an experiment. The equation y = 500(0.5)^x represents the remaining amount of compound A, in grams, after x hours. The table shows the remaining amount of compound B. What is the positive difference in the initial amount of each compound? Enter your answer in the box. __________ g

mikewwe13:

i'll send the pic

mikewwe13:

1 attachment
mikewwe13:

is it clear for you ?

Vocaloid:

so for compound A to find the initial amount just let x = 0 and find y

mikewwe13:

x = 0 = 0

Vocaloid:

y = 500(0.5)^x what does y equal when x = 0 ?

Vocaloid:

all you have to do is replace "x" with "0" and calculate y

mikewwe13:

what i've been trying to tell you is 0

mikewwe13:

my computer was acting crazy

Vocaloid:

it is not equal to 0

Vocaloid:

y = 500(0.5)^0 = ?

mikewwe13:

y = 500

Vocaloid:

good, so that's the initial value of compound A

mikewwe13:

ok

Vocaloid:

so for compound B we need to determine what the mass is at h = 0

Vocaloid:

since it's decreasing by half each hour, we have to double the mass at h = 1 to get the mass at h = 0 (since we are going backwards in time)

Vocaloid:

so the initial mass of B is 400 making the difference 500 - 400 = 100 = your answer.

mikewwe13:

so it's 400 g

mikewwe13:

or 100 g ?

Vocaloid:

100

mikewwe13:

ok 100 g ?

mikewwe13:

The linear function f(x) passes through the points (0,1) and (2,7). A few values from the exponential function g(x) are shown in the table. What is the positive difference in the y-intercept value of ​ f(x) ​and g(x) ​? Enter your answer in the box. _____

mikewwe13:

i'll the send pic

mikewwe13:

1 attachment
Vocaloid:

to find g(1) and g(0) we have to think in reverse since the value of g(x) is being doubled for every increase in x, we have to divide by 2 to get g(1) and g(0)

Vocaloid:

g(1) is (1/2) of g(2) and g(0) is (1/2) of g(1)

Vocaloid:

so if g(2) is 12 what is g(1)?

mikewwe13:

(1/2)

Vocaloid:

g(1) is ~one half~ the value of g(2) so if the value of g(2) is 12, what is the value of g(1)?

mikewwe13:

g(0)

Vocaloid:

to find g(1), take the value of g(2) and divide by 2

Vocaloid:

so if the value of g(2) is 12, what is the value of g(1)?

mikewwe13:

12/g

Vocaloid:

divide by 2, not divide by g.

mikewwe13:

6

Vocaloid:

good, now to find g(0) divide the value of g(1) by 2

mikewwe13:

3

Vocaloid:

good so the intercept of g(x) is 3 and the intercept of f(x) is 1 making the difference 2 = your answer

mikewwe13:

it's 2 ?

Vocaloid:

yes

mikewwe13:

ok

mikewwe13:

Which ordered pairs lie on the graph of the exponential function f(x)=128(0.5)^x ​ ? Select each correct answer. (0, 1) ​ ​ (1, 64) ​ ​ (3, 16) ​ ​​ (8, 0.5) ​

Vocaloid:

you just have to test each x value to see if it produces the matching y value

Vocaloid:

for example, for (0,1) let x = 0 and see if f(x) = 1

mikewwe13:

right

Vocaloid:

good, (0,1) works, now repeat these steps for the other points

mikewwe13:

(1,64) wrong​ ​ (3,16) ​correct ​​ (8,0.5) ​correct

Vocaloid:

128(0.5)^1 = ?

mikewwe13:

64

Vocaloid:

good, so (1,64) works all of the points work, actually

mikewwe13:

all of them ?

Vocaloid:

yes

mikewwe13:

https://static.k12.com/nextgen_media/assets/8078551-NG_AL1_SemA_06_UT_40.png Which function represents the graph of y=4^x−1 ? A. q B. r C. s D. t

mikewwe13:

btw the answer is C

Vocaloid:

is the -1 within the exponent or not?

mikewwe13:

yes

mikewwe13:

but i graphed it so it shows it's correct

Vocaloid:

as a hint try plugging in x = 0 and you'll get y = (1/4) making s not an option

Vocaloid:

there's only one graph that crosses (0,1/4)

mikewwe13:

i plugged it in so now i see it like this the choices: q, r, s, or t so it's not q s or r

Vocaloid:

you have to be careful with parentheses

Vocaloid:

y = 4^(x-1) try graphing this

mikewwe13:

oh ok now i get it

mikewwe13:

it's r

Vocaloid:

r is correct

mikewwe13:

https://static.k12.com/nextgen_media/assets/8079952-NG_AL1_SemA_06_UT_15.png The function f (x) = 5^(x−1) is shown on the coordinate plane. Select from the drop-down menus to correctly describe the end behavior of ​ f(x) ​. As x decreases without bound, the graph of f(x) Choose: approaches y = 0, increases without bound, or decreases without bound As x increases without bound, the graph of f(x) Choose: approaches y = 0, increases without bound, or decreases without bound

Vocaloid:

as x goes to -infinity, the graph approaches y = 0 but what about x going to + infinity? what happens as x gets bigger and bigger?

mikewwe13:

it increases

Vocaloid:

good so y "increases without bound"

Vocaloid:

so the first answer is "approaches y = 0" second is "increases without bound"

mikewwe13:

Let f(x)=8^x and g(x) = 8^x+5 + 1 . Which transformations are needed to transform the graph of f (x) to the graph of g (x) ? Select each correct answer. horizontal translation 5 units left vertical translation 5 units up horizontal translation 1 unit left horizontal translation 5 units right vertical translation 1 unit down vertical translation 1 unit up

Vocaloid:

anyway, since we add + 1 to the entire function it goes up 1 unit

mikewwe13:

the first one the third one the 5th one the 6th one

Vocaloid:

and since we add 5 to x (not from the entire function) it goes to the left by 5

mikewwe13:

the first one the third one the 5th one the 6th one 100% correct for sure

mikewwe13:

correct me

Vocaloid:

there are only two correct answers, a vertical transformation up by 1 and horizontal left by 5

mikewwe13:

the 6th one and the first one ?

Vocaloid:

right can we open a new question, this one is getting kind of laggy

mikewwe13:

ok sure

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!