https://static.k12.com/nextgen_media/assets/8078626-NG_AL1_J_06_U06_Quiz_03.png The graph shows the function g(x) . Select from the drop-down menu to correctly compare g(x) and f(x)=−3(x+1) . The y-intercept of f(x) is _____________ the y-intercept of g(x) . less than greater than equal to
@Vocaloid
I have answered this already, set x = 0 and calculate the y-intercept of f(x)
sorry i've been gone the time you've been answering me
and it's less than
good.
it's less than ?
yes.
could you help me if you're not busy ?
with more please with everything
sure
you're not busy with college or anything ?
today
I'm not busy right now
ok
The table shows the function g(x) . Select from the drop-down menu to correctly compare the growth factors for the exponential functions g(x) and f(x)=4(3)x . The growth factor of f(x) is __________________ the growth factor of g(x) . less than greater than equal to
i'll send the pic
f(x) = 4(3)^x
if you look at the table of g(x) each value is being multiplied by 4 to get to the next value making 4 the growth factor of g
if you look at f(x) each number is being multiplied by 3 (the number with the exponent x) making 3 the growth factor of f
equal to
please review what I have said carefully
oh wait no
it's greater than
the growth factor of f(x) is 3 the growth factor of g(x) is 4 therefore the growth factor of f(x) is ______ than g(x) fill in the blank
less than
good, that's it.
https://static.k12.com/nextgen_media/assets/8078601-NG_AL1_J_06_U06_Quiz_08.png One day, Fiona and Heidi each bought coins at a coin shop. The equation f(x) = 3x + 12 represents the value of Fiona’s coin, in dollars, x years later. The graph shows the value of Heidi’s coin, in dollars, x years later. Select from the drop-down menus to complete the statement. When they bought their coins, ( Fiona's or Heidi's ) coin was worth ( $3, $6, $9, or $12 ) more than ( Fiona's or Heidi's ) coin.
hint: calculate f(x) at year 0 (when x = 0)
f(0) = 0
re-read the problem please
f(x) = 3x + 12 calculate f(x) when x = 0.
-4
replace "x" with "0" and calculate f(x).
f(0)
now calculate f(0).
f(0) = 0
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid f(x) = 3x + 12 calculate f(x) when x = 0. \(\color{#0cbb34}{\text{End of Quote}}\)
copy down the original function replace "x" with 0 then calculate what the function is equal to.
f(x) f(0) like this ?
write this down: "f(x) = 3x + 12" replace the "x" with "0" whenever x shows up then calculate the function.
"f(x) = 3x + 12" = 12
good, f(0) = 12
now use the graph to find h(0).
so it's $12 right first ?
it is not $12 it is asking for the difference between heidi's coin and fiona's coin so we must subtract f(0) - h(0).
use the graph to find the value of heidi's coin at year 0
f(0) - h(0). = 0
again, use the graph to find the value of h(x) at x = 0.
ok i found it
what did you get as the value?
-10
correct me
-10 is not a value anywhere on the graph
put your finger on x = 0 then go up until you touch the graph what value do you get for h(x)?
6
good, that's h(0)
so if f(0) = 12 and h(0) = 6 f(0) - h(0) = ?
f6
just 6 but good
6 right
so fiona's coin is worth more than heidi's coin by $6
Compounds A and B are used in an experiment. The equation y = 500(0.5)^x represents the remaining amount of compound A, in grams, after x hours. The table shows the remaining amount of compound B. What is the positive difference in the initial amount of each compound? Enter your answer in the box. __________ g
i'll send the pic
is it clear for you ?
so for compound A to find the initial amount just let x = 0 and find y
x = 0 = 0
y = 500(0.5)^x what does y equal when x = 0 ?
all you have to do is replace "x" with "0" and calculate y
what i've been trying to tell you is 0
my computer was acting crazy
it is not equal to 0
y = 500(0.5)^0 = ?
y = 500
good, so that's the initial value of compound A
ok
so for compound B we need to determine what the mass is at h = 0
since it's decreasing by half each hour, we have to double the mass at h = 1 to get the mass at h = 0 (since we are going backwards in time)
so the initial mass of B is 400 making the difference 500 - 400 = 100 = your answer.
so it's 400 g
or 100 g ?
100
ok 100 g ?
The linear function f(x) passes through the points (0,1) and (2,7). A few values from the exponential function g(x) are shown in the table. What is the positive difference in the y-intercept value of f(x) and g(x) ? Enter your answer in the box. _____
i'll the send pic
to find g(1) and g(0) we have to think in reverse since the value of g(x) is being doubled for every increase in x, we have to divide by 2 to get g(1) and g(0)
g(1) is (1/2) of g(2) and g(0) is (1/2) of g(1)
so if g(2) is 12 what is g(1)?
(1/2)
g(1) is ~one half~ the value of g(2) so if the value of g(2) is 12, what is the value of g(1)?
g(0)
to find g(1), take the value of g(2) and divide by 2
so if the value of g(2) is 12, what is the value of g(1)?
12/g
divide by 2, not divide by g.
6
good, now to find g(0) divide the value of g(1) by 2
3
good so the intercept of g(x) is 3 and the intercept of f(x) is 1 making the difference 2 = your answer
it's 2 ?
yes
ok
Which ordered pairs lie on the graph of the exponential function f(x)=128(0.5)^x ? Select each correct answer. (0, 1) (1, 64) (3, 16) (8, 0.5)
you just have to test each x value to see if it produces the matching y value
for example, for (0,1) let x = 0 and see if f(x) = 1
right
good, (0,1) works, now repeat these steps for the other points
(1,64) wrong (3,16) correct (8,0.5) correct
128(0.5)^1 = ?
64
good, so (1,64) works all of the points work, actually
all of them ?
yes
https://static.k12.com/nextgen_media/assets/8078551-NG_AL1_SemA_06_UT_40.png Which function represents the graph of y=4^x−1 ? A. q B. r C. s D. t
btw the answer is C
is the -1 within the exponent or not?
yes
but i graphed it so it shows it's correct
as a hint try plugging in x = 0 and you'll get y = (1/4) making s not an option
there's only one graph that crosses (0,1/4)
i plugged it in so now i see it like this the choices: q, r, s, or t so it's not q s or r
you have to be careful with parentheses
y = 4^(x-1) try graphing this
oh ok now i get it
it's r
r is correct
https://static.k12.com/nextgen_media/assets/8079952-NG_AL1_SemA_06_UT_15.png The function f (x) = 5^(x−1) is shown on the coordinate plane. Select from the drop-down menus to correctly describe the end behavior of f(x) . As x decreases without bound, the graph of f(x) Choose: approaches y = 0, increases without bound, or decreases without bound As x increases without bound, the graph of f(x) Choose: approaches y = 0, increases without bound, or decreases without bound
as x goes to -infinity, the graph approaches y = 0 but what about x going to + infinity? what happens as x gets bigger and bigger?
it increases
good so y "increases without bound"
so the first answer is "approaches y = 0" second is "increases without bound"
Let f(x)=8^x and g(x) = 8^x+5 + 1 . Which transformations are needed to transform the graph of f (x) to the graph of g (x) ? Select each correct answer. horizontal translation 5 units left vertical translation 5 units up horizontal translation 1 unit left horizontal translation 5 units right vertical translation 1 unit down vertical translation 1 unit up
guide for function transformations: http://www.onlinemathlearning.com/image-files/xrules-transformation-function.png.pagespeed.ic.D7TvNh8Eh1.png
anyway, since we add + 1 to the entire function it goes up 1 unit
the first one the third one the 5th one the 6th one
and since we add 5 to x (not from the entire function) it goes to the left by 5
the first one the third one the 5th one the 6th one 100% correct for sure
correct me
there are only two correct answers, a vertical transformation up by 1 and horizontal left by 5
the 6th one and the first one ?
right can we open a new question, this one is getting kind of laggy
ok sure
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