Ask your own question, for FREE!
Mathematics 6 Online
mikewwe13:

Graph the piecewise function

mikewwe13:

@Vocaloid

mikewwe13:

1 attachment
mikewwe13:

what is the answer ?

Shadow:

Are you still there?

mikewwe13:

yes

Shadow:

Do you know how to do piecewise functions?

Shadow:

As far as graphing them?

mikewwe13:

no

Shadow:

https://www.youtube.com/watch?v=Gtyf0xCB0kc Watch this video. It is only six minutes, and he explains it really well. I am confident that you will be able to do them after this. Then I can check your work.

Shadow:

Though honestly, these are really simple. You just need a good teacher.

mikewwe13:

mikewwe13:

and i have a lot of other questions to be asked so really i can't really watch the video at this moment if you understand

mikewwe13:

so do you know how to help me with it instead of the video ?

Shadow:

It is a concept where it is best shown visually, and I suck at the drawing tool xD

Shadow:

So I would recommend watching the video. It really is not that long.

mikewwe13:

ok i just watched it

mikewwe13:

but do you know where vocaloid is

Shadow:

She appears to be unavailable at the moment. What part are you not getting about piecewise functions? Separate the information in the brackets into two groups. As stated in the video, you can call the expressions on the left the "behaviors" and the inequalities on the right "intervals." All you have to do is graph the lines, but only using those x values. For example 3x - 5 if x < or equal to -1 Graph the line, but using x values that are less than or equal to -1

Shadow:

Creating a graph in desmos so you can see it.

mikewwe13:

1 attachment
mikewwe13:

that's what exactly i did, is this correct ?

Shadow:

No.

Shadow:

Not for 3x -5 if x is less than or equal to -1

mikewwe13:

1 attachment
Shadow:

Yeah, so you would only graph the part of the line that falls under the blue area.

mikewwe13:

i've strolled and still don't see the graph

mikewwe13:

the line

Shadow:

I am having difficulty with the condition (interval) part being applied in desmos. But still, your most recent picture works. It would essentially end up looking like this. |dw:1511813649348:dw|

Shadow:

You don't graph the rest of the line, because think of it this way. That line only exists under that condition.

mikewwe13:

1 attachment
Shadow:

Yes, just the closed circle and the arrow going off to the south west

Shadow:

The reason I say closed is because the line is less than or EQUAL to -1. If it were just less than, we would leave the circle open (not filled in).

mikewwe13:

ok so this shows the correct way ?

Shadow:

Yes. Just be sure to erase the line that is intercepting the x axis. Also remember to draw the other intervals. Lastly, make notations on the x axis and label them (-1 for example, so your teacher knows where the closed dot is).

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!