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Mathematics 13 Online
Comerpickles:

http://prntscr.com/hhtyci What is the length of side BC of the triangle?

Comerpickles:

@YoursTruly

YoursTruly:

I'm no good at math. Sorry.

YoursTruly:

I'm no good at math. Sorry.

Comerpickles:

Its okay, do you know anyone who is?

Comerpickles:

At least the Mods or someone?

YoursTruly:

Ummm. @Arcadiouse

ThisGirlPretty:

@Zepdrix

Comerpickles:

Okie, thanks

Comerpickles:

@Arcadiouse

Comerpickles:

@Zepdrix

ThisGirlPretty:

I think zep will be on shortly.

Comerpickles:

Okie, thanks :)

ThisGirlPretty:

No problem ^_^

Zepdrix:

|dw:1512153458359:dw|In an isosceles triangles, the sides opposite the two equivalent angles are equal.

Zepdrix:

|dw:1512153542008:dw|For the triangle that was provided, our blue and red sides will be equivalent.

Zepdrix:

x+8 = 2x-1 Do you understand how to solve for x? That will get us halfway through the problem.

Comerpickles:

Yes, so far

Comerpickles:

They all equal 60, right?

Zepdrix:

No, that's for an `equilateral` triangle :) All three angles would be the same. This triangle is `isosceles`, which told us that two of the angles were the same. Which further tells us that two of the side lengths are the same. The side length \(\rm x+8\) is the same as the side length \(\rm 2x-1\). That's what allows us to equate them together like this, \(\large\rm x+8=2x-1\)

Zepdrix:

|dw:1512153896650:dw|

Zepdrix:

|dw:1512153928642:dw|

Zepdrix:

Applying a few algebra steps tells us that this previously unknown value x is 9. Since our third side (BC) relates to x, we can plug the value 9 in for x. \(\large\rm 3\color{orangered}{x}-3\quad=\quad 3\color{orangered}{\cdot9}-3\)

Comerpickles:

Wow, I'm so glad I asked for help. I totally got that. I guess these aren't that bad

Zepdrix:

Ya, just a little weird at first I guess :D

Comerpickles:

#IhateMath

Comerpickles:

XD

Zepdrix:

Pshhh you just jelly that math got style ;3

Zepdrix:

I don't know that means ;3 we'll pretend it made sense tho

Comerpickles:

XD

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