http://prntscr.com/hhtyci What is the length of side BC of the triangle?
@YoursTruly
I'm no good at math. Sorry.
I'm no good at math. Sorry.
Its okay, do you know anyone who is?
At least the Mods or someone?
Ummm. @Arcadiouse
@Zepdrix
Okie, thanks
@Arcadiouse
@Zepdrix
I think zep will be on shortly.
Okie, thanks :)
No problem ^_^
|dw:1512153458359:dw|In an isosceles triangles, the sides opposite the two equivalent angles are equal.
|dw:1512153542008:dw|For the triangle that was provided, our blue and red sides will be equivalent.
x+8 = 2x-1 Do you understand how to solve for x? That will get us halfway through the problem.
Yes, so far
They all equal 60, right?
No, that's for an `equilateral` triangle :) All three angles would be the same. This triangle is `isosceles`, which told us that two of the angles were the same. Which further tells us that two of the side lengths are the same. The side length \(\rm x+8\) is the same as the side length \(\rm 2x-1\). That's what allows us to equate them together like this, \(\large\rm x+8=2x-1\)
|dw:1512153896650:dw|
|dw:1512153928642:dw|
Applying a few algebra steps tells us that this previously unknown value x is 9. Since our third side (BC) relates to x, we can plug the value 9 in for x. \(\large\rm 3\color{orangered}{x}-3\quad=\quad 3\color{orangered}{\cdot9}-3\)
Wow, I'm so glad I asked for help. I totally got that. I guess these aren't that bad
Ya, just a little weird at first I guess :D
#IhateMath
XD
Pshhh you just jelly that math got style ;3
I don't know that means ;3 we'll pretend it made sense tho
XD
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