Square EFGH stretches vertically by a factor of 2.5 to create square E′F′G′H′. The square stretches with respect to the x-axis. If point H is located at (-2, 0), what are the coordinates of H′ ?

Question

jaynater · Answer

.-.

Angle · Answer

Hi @jarev0130 ! Welcome to QuestionCove! This is a weirdly phrased problem... first of all, since the original square is being vertically stretched (this means that only the y values of the coordinates are being changed), the resulting shape would be a rectangle and not a square. In any case, since this is being stretched vertically, the action might look something like: |dw:1512243221068:dw|

Angle · Answer

For this specific problem, because we are stretching based on the x axis AND it is only being stretched vertically:
the points on the x axis do not move at all

This should give you your answer for where the point H' will end up :)

Feel free to come back and ask anything you might not still understand. You can tag me with @Angle , I would be more than happy to help you ^_^