Mathematics
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zarkam21:
help
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zarkam21:
Vocaloid:
|dw:1512410863908:dw|
Vocaloid:
so find x = -b/2a where a is the coefficient of the x^2 term and b is the coefficient of the x term
zarkam21:
6
Vocaloid:
|dw:1512411275599:dw|
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Vocaloid:
|dw:1512411283947:dw|
Vocaloid:
-b/2a = -(-6)/(2*2) = ?
zarkam21:
solve for a or B?
Vocaloid:
x = -b/(2a)
you are asked to find x, so simply plug in a and b to find x
zarkam21:
-6
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Vocaloid:
b = -6
a = 2
-b/(2a) = ?
zarkam21:
-12/(2x1)
zarkam21:
-12/2
zarkam21:
-6
zarkam21:
@Vocaloid
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Vocaloid:
you might be doing a/2b instead of b/(2a)
-b/(2a) = -(-6)/(2*2) = -(-6)/4 = 3/2 = your ans
zarkam21:
okay and b is 12 correct?
Vocaloid:
b = -6
Vocaloid:
|dw:1512412994649:dw|
zarkam21:
and a is 2?
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Vocaloid:
yes
zarkam21:
it is dalse
Vocaloid:
hm.
zarkam21:
i put it into mathway and it is saying that the statement is false
Vocaloid:
that's odd, when I graph the equation it gives me x = (3/2) as the axis of symmetry :S
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zarkam21:
i don't know i put it into mathway with the substitutions and it says false
Vocaloid:
what exactly are you entering? can you show me your screen?
zarkam21:
Vocaloid:
Huh. Mathway is sometimes weird. Using good old-fashioned algebra gives me 3/2 though, you can also verify this by graphing the original equation.
Vocaloid:
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zarkam21:
Okay sounds good, so the answer is 3/2
Vocaloid:
yes