Well it cant be D
I'm thinking A/
I know its not D because it does not have the +-sign
if you solve the quadratic equation you get two complex roots
OKay so for problems like these i just solve for the quadratic equation and see how many roots I get
yes, in general complex roots come in pairs
i think it is a
Okay perfect thanks
OR you can graph them and see if the graph touches the x-axis
Okay and see how many times it touches??
no problem
in this case, the graph does not touch the x-axis at all so there cannot be any real roots
Got it. So it is D
wait hold on I graphed the wrong function ugh
when you graph/solve this you actually get two distinct, real roots ;_;
SO c/
yeah sorry about that ;;
No no don't worry about it ,, it was like the first mistake you ever made ;o
I need to go pick up lunch, hopefully blackghost can help rn
OKay thanks for everything
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