Help please
@Vocaloid
@Zepdrix
whats the question
vertex formula http://www.mathwarehouse.com/geometry/parabola/images/standard-vertex-forms.png
I posted it
well you know its a parabola so its going be negative since it is upside down
so which points do I use
@Vocaloid
@Vocaloid
let's start with intercept first
to find y-intercept , you have to substitute x=0 and solve for y OR the point where the graph intersects the y axis is called as y intercept
so can you identify the point where the graph meets the y axis ?
@563blackghost
The intercepts are where the parabola meets the x-axis. The vertex is where the parabola starts from. The axis of symmetry is the x-value of the vertex.
okay so intercepts would be (0,0)(-5,0) vertex (-1,-5)
Intercepts are correct. The vertex is incorrect. It is where the parabola starts.
okay so the vertex would be um
@Vocaloid
|dw:1512696925207:dw|
|dw:1512696934006:dw|
^axis of symmetry and vertex
(2,4.5)
should be (2.5,5) the y-axis isn't drawn well but each space is 1 unit
so that would be the vertex and axis of symmetry?
axis is just x = 2.5 vertex is (2.5,5)
Sounds good and my intercepts as (0,0,) (-5,0)
should be (5,0) not -5
make sure to specify: x intercepts: (0,0) and (5,0) y intercepts: (0,0)
oh okay @563blackghost said it was right that's why i was getting a second opinion
Perfect , thank you !
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