Could someone explain to me how to do this???Points A and A' have symmetry with respect to the line two units above, and parallel to, the x- axis. Graph the points for A', B', C', and D'. When A is (1, 1), A' is...? When B is (-3, 0), B' is...? When C is (3, 4), C' is...? When D is (-2, -1), D' is...? https://wca.sooschools.com/media/g_geo_ccss_2016/9/qu109a.gif
...kind of confusing..hmmm
Yeah I know.. I usualy dont have issues with this sort of graphing. But the A' B' thing has me kinda confused.
yea me too
the only thing i know is it's horizontal x'D but other than that i'm confused.
@Vocaloid a little help.
I thought it would be like the opposite like A (1,1) A' -1,-1 and then I figured that would be too easy, so that cant be right lol :')
Maybe you plot the point and create a line from it. You would then move the point 2 units down and get you line that parallel and respect from the line you created??? Such as A is (1,1) then we move down 2 units...(1,-1)???
That is the only thing I can think of.
Thats the other thing I was thinking.. Other than that I really don't even know :(
Well could you try to help me with this while I see if vocaloid can help me with the other one? I literally only have 3 questions left and these are the ones that have me stumped.. Here it is if so... http://prntscr.com/hmluhq
What have you put down so far. For the parabola one.
Is the desmos link for the parabola question?? I read thru it.. I'm still having a really hard time understanding how to do it though...
no that one is for the graphing one..
Oh okay... I'll read thru it again and I don't have anything down for the parabola yet, since it has me really confused.. Nothing like this was in lessons prior to it.
Here this should help: https://www.varsitytutors.com/hotmath/hotmath_help/topics/finding-the-equation-of-a-parabola-given-focus-and-directrix
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