Can someone explain how I do this?
for a) a rigid transformation means that the line is translated without changing the slope since all of the points are moved the exact same y-distance and x-distance. thus, since s and are parallel before they are also parallel after for b) and c) you will plug the points into the slope formula (this time we are using variables instead of numbers but the core concept is the same for d) line q is 3 units below line s, so take the coordinates for P' (make sure you are looking at P' not P) and subtract 3 from the y-coordinate to get P''
For d how am I supposed to subtract without any numbers though? Thats what I do not understand.
P' = (m, n + e) P'' = (m, n + e - 3)
and if e=3 then its just m,n?
e is not equal to 3 (none of the variables in this problem have assigned values) so you would just leave it like that
Wouldnt this mean e=3 though?
the original value for the P' coordinate is (m, n+e) the +e is not related to the translation 3 down
ah ok
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