Question

help pre cal

Answer 1

where is the question

Answer 2

@Shadow

Answer 3

For this question you need to use the Law of Sines. Do you know what that is?

Answer 4

yes i just need my answers checked

Answer 5

\[\frac{ \sin 90 \times 12 }{ \sin 15 } = c\]

Answer 6

You are correct on the first one

Answer 7

yay

Answer 8

2 . tan x =10/7=55

Answer 9

am i correct

Answer 10

Since C is a right angle, we know that c is the hypotenuse. Therefore

\[\sqrt (a + b) = c\]
\[12.2 = c\]

We get:

\[\frac{ \sin B }{ 10 } = \frac{ \sin 90 }{ 12.2 }\]

\[10\sin 90 = 12.2 \sin B\]

\[\frac{ 10 }{ 12.2 } = \sin B\]

\[\sin^{-1} (\frac{ 10 }{ 12.2 }) = 55.05\]

Answer 11

well that works too lol

Answer 12

3 i used a^2+b^2=c^2

Answer 13

is 3 correct

Answer 14

A = \[A = 180 - 90 - 30 = 60\]

\[\frac{ \sin 30 }{ b } = \frac{ \sin 90 }{ 10 }\]

\[b = \frac{ 10\sin30 }{ \sin90 } = 5\]

\[a^2 + 25 = 100\]

\[a^2 = 75\]

\[a = 8.6602\]

Answer 15

Also the correct form of the formula I used earlier is:

\[c = \sqrt (a^2 + b^2)\]

Answer 16

so d is correct omg how many answers are d i have 2 more to check lol

Answer 17

ok all answers correct so far?

Answer 18

4 d 5 a

Answer 19

\[\frac{ \sin40 }{ 50 } = \frac{ \sin90 }{ c }\]

\[c \sin40 = 50\sin90 \]

\[c = \frac{ 50\sin90 }{ \sin40 }\]

c = about 78 miles

Answer 20

\[2500 + b^2 = 6084\]

b = about 60 miles

Answer 21

5?

Answer 22

you there

Answer 23

@Shadow

Answer 24

\[\frac{ \sin42 }{ 15 } = \frac{ \sin90 }{ c }\]

\[c \sin42 = 15 \sin90\]

\[c = \frac{ 15 \sin 90 }{ \sin42 }\]

\[c = 22.4\]

Answer 25

so all are correct

Answer 26

dddda

Answer 27

right?

Answer 28

\[225 + b^2 = 501.76 \]
\[b^2 = 276.76\]
\[b = 16.7\]

Answer 29

Yes, you did a good job.

Answer 30

if i need your help again ill start a new post