zarkam21:

? A point at the end of a propeller has a centripetal acceleration of 532.6 m/s^2. If the velocity of the propeller at this point is 35 m/s, how long is the propeller blade?

4 months ago
zarkam21:

1 attachment
4 months ago
zarkam21:

@Shadow

4 months ago
Nnesha:

img008.JPG

4 months ago
sillybilly123:

|dw:1516670034581:dw|

4 months ago
zarkam21:

so C

4 months ago
zarkam21:

@Nnesha @Vocaloid

4 months ago
Nnesha:

wha formula did you use? and how did you get 1.9m?

4 months ago
zarkam21:

i used the one in the pic

4 months ago
Nnesha:

alright so how did you setup the values ?

4 months ago
zarkam21:

like this

4 months ago
zarkam21:

9.8=35^2/532.6

4 months ago
Nnesha:

\[9.8 \cancel{=}35^2/532.6\]

4 months ago
Nnesha:

\[\frac{ (35)^2 }{ 532.6} \cancel{=} 9.8\]

4 months ago
zarkam21:

0.13

4 months ago
Vocaloid:

a = v^2/r in this case a is the centripetal acceleration given in the problem, v is the velocity of the propeller (also given) and you must solve for r

4 months ago
zarkam21:

532.6=35^2/r

4 months ago
Vocaloid:

awesome, now solve for r

4 months ago
zarkam21:

2.3

4 months ago
Vocaloid:

good, so D

4 months ago
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