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zarkam21:
? A point at the end of a propeller has a centripetal acceleration of 532.6 m/s^2. If the velocity of the propeller at this point is 35 m/s, how long is the propeller blade?
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zarkam21:
zarkam21:
@Shadow
Nnesha:
sillybilly123:
|dw:1516670034581:dw|
zarkam21:
so C
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zarkam21:
@Nnesha @Vocaloid
Nnesha:
wha formula did you use? and how did you get 1.9m?
zarkam21:
i used the one in the pic
Nnesha:
alright so how did you setup the values ?
zarkam21:
like this
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zarkam21:
9.8=35^2/532.6
Nnesha:
\[9.8 \cancel{=}35^2/532.6\]
Nnesha:
\[\frac{ (35)^2 }{ 532.6} \cancel{=} 9.8\]
zarkam21:
0.13
Vocaloid:
a = v^2/r in this case a is the centripetal acceleration given in the problem, v is the velocity of the propeller (also given) and you must solve for r
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zarkam21:
532.6=35^2/r
Vocaloid:
awesome, now solve for r
zarkam21:
2.3
Vocaloid:
good, so D
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