Ask your own question, for FREE!
Mathematics 14 Online
hardlyhuman:

Geometry help please

hardlyhuman:

1 attachment
Vocaloid:

MN is a line segment so all the points are contained between M and N making D the best option imo

hardlyhuman:

Okay thanks, I'll post the next one;

hardlyhuman:

1 attachment
Vocaloid:

imagine a reflection like a mirror the first two choices show two mirror images the option you chose is a translation not a reflection

hardlyhuman:

Okay, would it be the first one?

Vocaloid:

|dw:1516814709229:dw|

hardlyhuman:

Okay I see now, thank you. I'll post the next one

1 attachment
Vocaloid:

for these problems it's 360/number of sides so 360/18 - > 20 --> your answer

hardlyhuman:

1 attachment
Vocaloid:

Hm. technically all of these could work BUT you are given two right triangles with equal hypotenuse and one equal leg (the shared side in the middle) so my best guess is HL

hardlyhuman:

1 attachment
Vocaloid:

if you compare the old coordinates to the new coordinates, every old coordinate got divided by a number, what is that number?

hardlyhuman:

I honestly don't know,

Vocaloid:

just compare the first coordinate of A 2/0.5 = ?

hardlyhuman:

4

hardlyhuman:

right?

Vocaloid:

good, that means each coordinate got divided by 4, so the dilation factor = (1/4) = your answer

hardlyhuman:

do i write it as (1/4) or 1/4?

Vocaloid:

probably just 1/4 or 0.25 I'm just putting the parentheses for clarity

hardlyhuman:

Oh okay, thank you.

1 attachment
Vocaloid:

|dw:1516816028137:dw|

Vocaloid:

basically, the new x-coordinate = sum of old x-coordinates, then divided by 2 new y-coordinate = sum of old y-coordinates, then divided by 2

hardlyhuman:

and how would i set that up? i know its probably irritating to have to explain everything but im not joking when i said im horrible at math. i dont understand this crap and im just trying to get though the rest of the year.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!