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Mathematics 16 Online
kaylak:

7 questions trig

kaylak:

@Vocaloid

kaylak:

1 attachment
kaylak:

1 attachment
Vocaloid:

let's just take it one at a time ^_^ to figure out 1 we just need to draw a triangle with sides a b c and angles A B C in the appropriate positions

kaylak:

1 attachment
kaylak:

is 1 a?

Vocaloid:

hold on I'm trying to figure out (just need to get this clown out first)

kaylak:

okay take your time

Vocaloid:

|dw:1516982598826:dw|

Vocaloid:

since cos(B) = adjacent/hypotenuse = 15/c we need to find the hypotenuse of the triangle do you remember the pythagorean theorem?

kaylak:

yes lol

Vocaloid:

good, then find the hypotenuse (c)

kaylak:

it would be d then lol

Vocaloid:

awesome, D for 2 we also need to draw a sketch of the situation

Vocaloid:

|dw:1516982999862:dw|

Vocaloid:

since we have: the angle, and the side opposite the angle, and we want to know the hypotenuse we can use sin(theta) = opposite/hypotenuse, plug everything in and solve for hypotenuse

kaylak:

is the answer b?

Vocaloid:

check your calculations again sin(30) = 10/x solve for x

kaylak:

it's a 20

Vocaloid:

good

Vocaloid:

for 3) as usual we will start with a sketch of the situation

Vocaloid:

|dw:1516983289670:dw|

Vocaloid:

|dw:1516983323669:dw|

kaylak:

i got b

Vocaloid:

we have: the angle the opposite to the angle and we want to find the hypotenuse sin(55) = 16/c

kaylak:

yep that's what i did

kaylak:

its b

Vocaloid:

yup B

Vocaloid:

4) |dw:1516983427855:dw|

kaylak:

5 is also b

Vocaloid:

we haven't done 4 yet ^^

Vocaloid:

we have opposite and adjacent, so we can also use cos cos(theta) = 6/10 do you know how to solve for theta?

kaylak:

i need a refresher lol

Vocaloid:

the inverse of cos is arccos arccos(cos(theta)) = theta so take the arccos of both sides to get theta = arccos(6/10) = 53.1 (answer C)

kaylak:

okay is 5 b

Vocaloid:

gimme a sec let me sketch it out

Vocaloid:

|dw:1516983789902:dw|

Vocaloid:

that's not quite what I got tan(theta) = opposite/adjacent, solve for theta

kaylak:

oh i used sin okay

kaylak:

is it a then

Vocaloid:

good

Vocaloid:

have you tried #6 yet

kaylak:

not yet

Vocaloid:

first take the arcsin of each side to solve for theta

kaylak:

so b i guess isn't right lol

kaylak:

i basically do 3/5=.60 and then take sin by the choices till i get one that matches lol

Vocaloid:

arcsin(3/5) = ?

kaylak:

so the opposite right

Vocaloid:

what do you get when you punch arcsin(3/5) into your calculator?

kaylak:

36.9

Vocaloid:

good, however, it wants the OTHER angle, so we must subtract 90 - 36.9 = your answer

kaylak:

im using mathway but yes lol

kaylak:

so about 53 lol

kaylak:

53.1 lol

Vocaloid:

good, so C

Vocaloid:

for 7 let's do another sketch |dw:1516984379704:dw|

Vocaloid:

|dw:1516984403389:dw|

kaylak:

that makes sense becayse question 4 was 6/10 which is 3/5 lol

Vocaloid:

try solving for A where sin(A) = 4/8

kaylak:

30

Vocaloid:

angle A is 30, which means B is the only possibility

kaylak:

i was about to say lol

kaylak:

thank you

Vocaloid:

8 is right

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