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Two cubes have side lengths that are equal to 2x and 4x. How many times greater than the surface of the small cube is the surface area of the large cube?
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Surface area of a cube = \(6\times (side)^2\) You have the sides given as 2x and 4x
so you can plug in those values and find the two surface areas and then find the ratio of areas of big and small cube that'd be your answer
so would I get 24x^2 amd 96x^2?
Yes
From that you can tell how many times greater is the surface area of bigger cube
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