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Mathematics 19 Online
zarkam21:

?

zarkam21:

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Vocaloid:

|dw:1517235348696:dw|

zarkam21:

A

Vocaloid:

good

zarkam21:

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zarkam21:

@Vocaloid

Vocaloid:

first step is to bring the coefficients up as exponents

Vocaloid:

|dw:1517235682470:dw|

Vocaloid:

|dw:1517235722808:dw|

Vocaloid:

then we use rules 1 + 2 to move everything into one log basically if there's a plus sign before the log it goes in the numerator and if there's a minus sign it goes in the denominator of the new log

Vocaloid:

let me know if you get stuck

zarkam21:

D

zarkam21:

Sorry it took me a while

Vocaloid:

good

zarkam21:

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zarkam21:

A

Vocaloid:

good

zarkam21:

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Vocaloid:

hint: a log written w/o a base is assumed to have a base of 10

zarkam21:

so 10

Vocaloid:

good

Vocaloid:

hm hold on

zarkam21:

oh alright

Vocaloid:

it should be 10 mathematically but when I check my calc I get something else :S

Vocaloid:

anyway let's stick with 10 for now, I'll try and see what's wrong with my input

zarkam21:

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Vocaloid:

re-write both in terms of base 10 (the logs cancel out on the left side) (M/N) = 10^5 (P/N) = 10^7 so M/N = 10^5 and P/N = 10^7 judging by this, what can you say about the relation between P and M?

zarkam21:

A

Vocaloid:

awesome

zarkam21:

1 attachment
Vocaloid:

|dw:1517237271634:dw|

Vocaloid:

there are two correct answer choices, let me know if you get stuck

zarkam21:

A and C

Vocaloid:

almost the exponent rule requires that the p exponent only applies to the inside of the log so A +B

zarkam21:

is that all the statements?

Vocaloid:

yeah that's it

Vocaloid:

I'm going to go talk to my prof about something I'll try to be back later this afternoon

zarkam21:

okay

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