http://prntscr.com/ibh8ja
can you please just show everything on the graph in one shot. Thanks
I'm not allowed to do the whole thing at once for you, that is against the rules. I am however willing to walk you through it. Start by graphing the two equations as normal.
Yes please
once you have the two lines, change y = 8x - 5 to a dotted line and y = -9x + 10 remains a solid line then shade underneath y = 8x - 5 and above y = -9x + 10
can you show on graph? please
|dw:1518023199509:dw|
|dw:1518023214751:dw| that's how you shade below the first line now try with the second one I am willing to help but I am not going to do all the work, it's your assignment not mine
the right side is shaded right?
yes, since the inequality sign is y< we shade "below" the graph, which looks like the right side
that is not the correct line, try drawing it again
if you are trying to graph y < 8x - 5 the y-intercept is -5 and the slope is 8
start over, erase the orange and blue lines the y-intercept (not the x-intercept) needs to be -5 so the graph needs to cross (0,-5)
|dw:1518023570988:dw|
|dw:1518023576703:dw|
slope of 8 means we go up 8 units and right 1 unit
|dw:1518023603305:dw|
then connect the lines with a dashed line (not solid)
|dw:1518023622793:dw|
now try the other inequality y >= -9x + 10 first start by graphing y = -9x + 10
how about the second line?
again, start by graphing y = -9x + 10
im having trouble tbh
that's fine, I am glad you are speaking up this equation is in the form y = mx + b so y = -9x + 10 the slope is -9 and the y-intercept is 10 start by plotting the y-intercept at (0,10)
just start by putting a point at (0,10)
okay whats next?
since the slope is -9 go down 9 units, and 1 unit to the right then plot another point then connect the two points with a straight line please show me the completed graph
the point (0,10) is on the y-axis not the x-axis
good, now draw a straight line that goes through those two points you will also have to re-do the orange line b/c that's not the first line
so how should it look like?
|dw:1518054562000:dw| I have already graphed the first line.
it should have slope 8 and y-intercept -5
okay
please show me a graph with both lines when you are finished
the orange line is still incorrect plot a line with a y-intercept at (0,-5) with a slope of 8
plot (0,-5) <--- this is on the y-axis not the x-axis then go up 8 and to the right 1 then plot another point then create a line that goes through the two points AND goes to infinity in both directions
can you just show me? i have 10 questions on these..this is only my second :( and i have to get this done. smh
|dw:1518055071624:dw|
go over 1 and up 8.
|dw:1518055097400:dw|
then connect the two points with a straight line that goes to infinity in both directions.
|dw:1518055123354:dw|
okay done that.
now, take the graph of y = 8x - 5 and change to a dotted line leave y = -9x + 10 a solid line then shade below y = 8x - 5 and above y = -9x + 10.
okay and thats the end of this question?
after the shading/dotting is done then yes
thanks, can we please go to the next question? but do it a little faster haha
The more you participate the faster this will be.
Btw whats your name?
Let's just get to the next question please.
alright y >= 0 means a solid line at y = 0 x >= 0 means a solid line at x = 0 x < 2 means a dashed line at x = 2 remember that x = ___ is a vertical line and y = ___ is a horizontal line
i think that the line would go straight through the x-axis?
y = 0 does, yes
x = 0 goes through the y-axis then x = 2 goes through the x-value 2
so far so good
so whats next?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid x = 0 goes through the y-axis then x = 2 goes through the x-value 2 \(\color{#0cbb34}{\text{End of Quote}}\) you still need to plot x = 0 and x = 2.
can you show me?
please
you drew y = 0 which went through the x-axis, right? x = 0 goes through the other axis
|dw:1518056275172:dw|
and then x = 2 is just a vertical line at x = 2, I know you can draw this one
okay and is there a shaded part?
for y = 0 since it's y >= 0 shade above this line for x = 0 since it's x >= 0 shade to the right of this line for x = 2 since it's actually x < 2 shade below the line
^ the graph he is posting is incorrect btw, all of the lines in this question are completely horizontal or vertical :
ohh
can you show me the shaded parts?+
let's start with y = 0
|dw:1518056727108:dw|
for x >= 0 shade to the right
|dw:1518056778543:dw|
|dw:1518056786171:dw|
|dw:1518056810367:dw|
|dw:1518056816801:dw|
then put all the graphs together
Here you go :^)
thanks
can we open a new question? sorry this one is starting to lag :S
okay
Join our real-time social learning platform and learn together with your friends!