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Mathematics 5 Online
johnnn:

http://prntscr.com/ibh8ja

johnnn:

can you please just show everything on the graph in one shot. Thanks

Vocaloid:

I'm not allowed to do the whole thing at once for you, that is against the rules. I am however willing to walk you through it. Start by graphing the two equations as normal.

johnnn:

Yes please

Vocaloid:

once you have the two lines, change y = 8x - 5 to a dotted line and y = -9x + 10 remains a solid line then shade underneath y = 8x - 5 and above y = -9x + 10

johnnn:

can you show on graph? please

Vocaloid:

|dw:1518023199509:dw|

Vocaloid:

|dw:1518023214751:dw| that's how you shade below the first line now try with the second one I am willing to help but I am not going to do all the work, it's your assignment not mine

johnnn:

the right side is shaded right?

Vocaloid:

yes, since the inequality sign is y< we shade "below" the graph, which looks like the right side

johnnn:

is this correct? http://prntscr.com/ibhdco

Vocaloid:

that is not the correct line, try drawing it again

Vocaloid:

if you are trying to graph y < 8x - 5 the y-intercept is -5 and the slope is 8

johnnn:

http://prntscr.com/ibhejn

Vocaloid:

start over, erase the orange and blue lines the y-intercept (not the x-intercept) needs to be -5 so the graph needs to cross (0,-5)

Vocaloid:

|dw:1518023570988:dw|

Vocaloid:

|dw:1518023576703:dw|

Vocaloid:

slope of 8 means we go up 8 units and right 1 unit

Vocaloid:

|dw:1518023603305:dw|

Vocaloid:

then connect the lines with a dashed line (not solid)

Vocaloid:

|dw:1518023622793:dw|

Vocaloid:

now try the other inequality y >= -9x + 10 first start by graphing y = -9x + 10

johnnn:

how about the second line?

Vocaloid:

again, start by graphing y = -9x + 10

johnnn:

im having trouble tbh

Vocaloid:

that's fine, I am glad you are speaking up this equation is in the form y = mx + b so y = -9x + 10 the slope is -9 and the y-intercept is 10 start by plotting the y-intercept at (0,10)

johnnn:

http://prntscr.com/ibnxpw correct?

Vocaloid:

just start by putting a point at (0,10)

johnnn:

okay whats next?

Vocaloid:

since the slope is -9 go down 9 units, and 1 unit to the right then plot another point then connect the two points with a straight line please show me the completed graph

johnnn:

http://prntscr.com/ibnztt

Vocaloid:

the point (0,10) is on the y-axis not the x-axis

johnnn:

http://prntscr.com/ibo0ay

Vocaloid:

good, now draw a straight line that goes through those two points you will also have to re-do the orange line b/c that's not the first line

johnnn:

so how should it look like?

Vocaloid:

|dw:1518054562000:dw| I have already graphed the first line.

Vocaloid:

it should have slope 8 and y-intercept -5

johnnn:

okay

Vocaloid:

please show me a graph with both lines when you are finished

johnnn:

http://prntscr.com/ibo1zp

Vocaloid:

the orange line is still incorrect plot a line with a y-intercept at (0,-5) with a slope of 8

Vocaloid:

plot (0,-5) <--- this is on the y-axis not the x-axis then go up 8 and to the right 1 then plot another point then create a line that goes through the two points AND goes to infinity in both directions

johnnn:

can you just show me? i have 10 questions on these..this is only my second :( and i have to get this done. smh

Vocaloid:

|dw:1518055071624:dw|

Vocaloid:

go over 1 and up 8.

Vocaloid:

|dw:1518055097400:dw|

Vocaloid:

then connect the two points with a straight line that goes to infinity in both directions.

Vocaloid:

|dw:1518055123354:dw|

johnnn:

okay done that.

Vocaloid:

now, take the graph of y = 8x - 5 and change to a dotted line leave y = -9x + 10 a solid line then shade below y = 8x - 5 and above y = -9x + 10.

johnnn:

okay and thats the end of this question?

Vocaloid:

after the shading/dotting is done then yes

johnnn:

thanks, can we please go to the next question? but do it a little faster haha

Vocaloid:

The more you participate the faster this will be.

johnnn:

Btw whats your name?

Vocaloid:

Let's just get to the next question please.

johnnn:

http://prntscr.com/ibo54v

Vocaloid:

alright y >= 0 means a solid line at y = 0 x >= 0 means a solid line at x = 0 x < 2 means a dashed line at x = 2 remember that x = ___ is a vertical line and y = ___ is a horizontal line

johnnn:

i think that the line would go straight through the x-axis?

Vocaloid:

y = 0 does, yes

Vocaloid:

x = 0 goes through the y-axis then x = 2 goes through the x-value 2

johnnn:

http://prntscr.com/ibo6dw

Vocaloid:

so far so good

johnnn:

so whats next?

Vocaloid:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @Vocaloid x = 0 goes through the y-axis then x = 2 goes through the x-value 2 \(\color{#0cbb34}{\text{End of Quote}}\) you still need to plot x = 0 and x = 2.

johnnn:

can you show me?

johnnn:

please

Vocaloid:

you drew y = 0 which went through the x-axis, right? x = 0 goes through the other axis

Vocaloid:

|dw:1518056275172:dw|

Vocaloid:

and then x = 2 is just a vertical line at x = 2, I know you can draw this one

johnnn:

okay and is there a shaded part?

Vocaloid:

for y = 0 since it's y >= 0 shade above this line for x = 0 since it's x >= 0 shade to the right of this line for x = 2 since it's actually x < 2 shade below the line

Vocaloid:

^ the graph he is posting is incorrect btw, all of the lines in this question are completely horizontal or vertical :

johnnn:

ohh

Bob:

http://prntscr.com/ibh8ja we're doing this

johnnn:

can you show me the shaded parts?+

Vocaloid:

let's start with y = 0

Vocaloid:

|dw:1518056727108:dw|

Vocaloid:

for x >= 0 shade to the right

Vocaloid:

|dw:1518056778543:dw|

Vocaloid:

|dw:1518056786171:dw|

Vocaloid:

|dw:1518056810367:dw|

Vocaloid:

|dw:1518056816801:dw|

Vocaloid:

then put all the graphs together

Bob:

Here you go :^)

johnnn:

thanks

johnnn:

http://prntscr.com/iboc9u

Vocaloid:

can we open a new question? sorry this one is starting to lag :S

johnnn:

okay

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