Question

A spinner has 8 equal sectors labeled from 1 to 8. The spinner is spun twice.

What is the probability of getting an even number on the first spin and another even number on the second spin?

Answer 1

for this event you need to consider both spins separately

what's the probability of getting even on one spinner with sections labelled 1-8?

Answer 2

Wouldn't you have like a 4/8 chance of landing on an even number

Answer 3

let's let the op try to figure it out ^_^

Answer 4

sorry i was doing something but umm i'd be guessing. would it be an odd number out of 8?

Answer 5

let's list out the outcomes for the spinner:

1,2,3,4,5,6,7,8

how many even numbers are there?

Answer 6

4

Answer 7

oh so it'd be 4 sorry i'm dumb lol

Answer 8

good, so for the first spinner the probability is (4/8) or (1/2)

for the second spinner, the probability is the same (independent events)

so (1/2)*(1/2) = (1/4) = your answer

Answer 9

Thats what i was thinking, but it sounded to easy at first.

Answer 10

omg that's actually very simple thank you so much