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@563blackghost
@563blackghost
Change the first equation to an equation of y. \(\large\bf{y-x=9}\) Add `x` to each side. \(\large\bf{y=x+9}\) Now you would plug this equation into the second equation. Simplify to find `x`. \(\large\bf{10+2x=-2(x+9)}\)
10+2x=-2x+(-18)
Right...continue :3 though `-2x+(-18)` is simply `-2x-18`
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2x=-2x-28
yup
We need to isolate `x`. So let's get the like terms on one side. We have the term without variables on one side already, but not the one with terms. So we would `add 2x to each side`. \(\large\bf{2x {\color{red}{~+2x}=-2x{\color{red}{~+2x}-28}}}\) \(\large\bf{4x=-28}\)
Divide each side by 4 to find x.
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righty?
yurps :3
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