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Mathematics 13 Online
eduD:

http://prntscr.com/icjktv

eduD:

@563blackghost

eduD:

@563blackghost

563blackghost:

Change the first equation to an equation of y. \(\large\bf{y-x=9}\) Add `x` to each side. \(\large\bf{y=x+9}\) Now you would plug this equation into the second equation. Simplify to find `x`. \(\large\bf{10+2x=-2(x+9)}\)

eduD:

10+2x=-2x+(-18)

563blackghost:

Right...continue :3 though `-2x+(-18)` is simply `-2x-18`

eduD:

2x=-2x-28

563blackghost:

yup

563blackghost:

We need to isolate `x`. So let's get the like terms on one side. We have the term without variables on one side already, but not the one with terms. So we would `add 2x to each side`. \(\large\bf{2x {\color{red}{~+2x}=-2x{\color{red}{~+2x}-28}}}\) \(\large\bf{4x=-28}\)

563blackghost:

Divide each side by 4 to find x.

eduD:

-7

eduD:

righty?

563blackghost:

yurps :3

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