Question

Quick Unit Conversion Question

Answer 1

I found this solution to a hw problem and I have no idea where they got that J to cm^(-1) conversion factor @sillybilly123

Answer 2

they're using inverse of wavelength as a proxy for energy

So \(E = h f = h \dfrac{c}{\lambda}\)

and, because h and c are constants, you then have:

\(\dfrac{E} {hc} = \dfrac{1}{\lambda}\)

all ties in with the actual values of those constants in your calculation