Question

a 0.050Kg yo-yo is swung in a vertical circle on the end of its 0.30m long string at te slowest speed that the yo-yo can have.
a) What is the speed of yo-yo at the bottom of the circular path?

I know that the yo-yo will rotate in a vertical circle with the slowest speed when the tension of the string at the top of the circular path is 0 nad it is 0. The only force acting on the yo-yo at the top is the force of gravity and hence the centripetal acceleration at the top would be g.

So how do i calculate the monimum speed of the yoyo at the bottom of its circular path so it maintains its circular motion?

Answer 1

put those thoughts into equations

Answer 2

if i knew how to do that, i'dn't be here........

Answer 3

seriously?

Answer 4

yupp

Answer 5

"I know that the yo-yo will rotate in a vertical circle with the slowest speed when the tension of the string at the top of the circular path is 0 nad it is 0. The only force acting on the yo-yo at the top is the force of gravity and hence the centripetal acceleration at the top would be g."

Answer 6

ok i know that when the yoyo is at the bottom of its circular path...it should be Ft - Fg

Answer 7

clever ! you got friction in there !

Answer 8

where is the friction?

Answer 9

it's literally hanging in the air

Answer 10

i think it should be Fc = Ft - Fg

Answer 11

but it doesn't add up when i plugin the numbers.

Answer 12

did it ever occur to you to draw it?

Answer 13

i have...but i can't draw it here....it's too difficult

Answer 14

yes.

just one of the many difficulties.

Answer 15

*I know that the yo-yo will rotate in a vertical circle *

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