Part A: The area of a square is (9x^2 24x 16) square units. Determine the length of each side of the square by factoring the area expression completely. Show your work. (5 points) Part B: The area of a rectangle is (16x^2 − 25y^2) square units. Determine the dimensions of the rectangle by factoring the area expression completely. Show your work. (5 points)
Brainliest? >.>
hehe
@Elsa213 my mistake sorry
@Elsa213 can you help me with the question please
``` 9x^2 + 24x + 16 = (3x + 4)(3x + 4) length of each side = 3x + 4 units. Par B 16x^2 - 25y^2 = (4x + 5y )( 4x - 5y) length = 4x + 5y and width = 4x - 5y ``` Source: Google
thank you so much! :)
i have one more question :)
An expression is shown below: f(x) = 5x^2 + 2x − 3 Part A: What are the x-intercepts of the graph of f(x)? Show your work. (2 points) Part B: Is the vertex of the graph of f(x) going to be a maximum or minimum? What are the coordinates of the vertex? Justify your answers and show your work. (3 points) Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph. (5 points)
@Elsa213
Part A: To find x intercepts, first factor 5x^2 + 2x − 3 (5x - 3)(x + 1) Solve for x 5x - 3 = 0 5x = 3 x = 3/5 x + 1 = 0 x = -1 So 3/5 and -1
ok awesome thats part a :)
Yes now since the first term is positive, that means the graph is going in a U shape and it has a minimum
Which is at (-0.2, -3.2)
To show the work to find x it is x = -b/2a so x = -2/2*5 x = -0.2 Plug that in for x and you get y = -3.2
Part C, to graph you would plot the x intercepts and minimum and then if you want more points just put any number for x, find the y and plot
ok so wait for part b, its..?
@Mehek
\(\color{#0cbb34}{\text{Originally Posted by}}\) @Mehek Yes now since the first term is positive, that means the graph is going in a U shape and it has a minimum \(\color{#0cbb34}{\text{End of Quote}}\)
And then everything after that before the "part C"
ok perfect thank you so much
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