A boat floats south on the Amazon River at a speed of 6 m/s. The boat and passengers have a combined mass of 540 kg. a. What is the momentum of the boat? (Remember, momentum is a vector quantity.) b. The passengers paddle backward, reducing the speed to 4 m/s. What was the impulse applied to the boat by the paddling?
Do you know the formula for momentum?
@zarkam21
p=mv
so 540*6?
Yes, and make sure to remember what they noted in (a)
so 3240kg m/s
because momentum is a vector quantity
What must you include then?
3240kg m/s south
Correct
Now for (b), what direction are the passengers paddling in?
backwards?
Yes, North. Now, do you know what impulse is?
Isn't it Newtons Second Law of Physics
Impulse is also the change in momentum
mhm
\[J = F \times \Delta T = m \Delta V\]
That's the formula for impulse. We can disregard Force multiplied by Time.
j=540*4 j=1620
Incorrect
Can you take a guess as to why?
well the delta sign
What does that sign mean?
change in velocity
What was the change in velocity for this problem?
6-4=2?
\[\Delta V = V _{f} - V _{i} = 6 - 4 = 2m/s\]
Yes, so what would our setup be for impulse?
540*2
j=540*2 j=1080
There you go
the unit would be n right?
Use the units of mass times velocity (kg times m/s)
so 1080 kg m/s
Yes
=) Thank you so much
No problem
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