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zarkam21:

A boat floats south on the Amazon River at a speed of 6 m/s. The boat and passengers have a combined mass of 540 kg. a. What is the momentum of the boat? (Remember, momentum is a vector quantity.) b. The passengers paddle backward, reducing the speed to 4 m/s. What was the impulse applied to the boat by the paddling?

Shadow:

Do you know the formula for momentum?

Shadow:

@zarkam21

zarkam21:

p=mv

zarkam21:

so 540*6?

Shadow:

Yes, and make sure to remember what they noted in (a)

zarkam21:

so 3240kg m/s

zarkam21:

because momentum is a vector quantity

Shadow:

What must you include then?

zarkam21:

3240kg m/s south

Shadow:

Correct

Shadow:

Now for (b), what direction are the passengers paddling in?

zarkam21:

backwards?

Shadow:

Yes, North. Now, do you know what impulse is?

zarkam21:

Isn't it Newtons Second Law of Physics

zarkam21:

Impulse is also the change in momentum

Shadow:

mhm

Shadow:

\[J = F \times \Delta T = m \Delta V\]

Shadow:

That's the formula for impulse. We can disregard Force multiplied by Time.

zarkam21:

j=540*4 j=1620

Shadow:

Incorrect

Shadow:

Can you take a guess as to why?

zarkam21:

well the delta sign

Shadow:

What does that sign mean?

zarkam21:

change in velocity

Shadow:

What was the change in velocity for this problem?

zarkam21:

6-4=2?

Shadow:

\[\Delta V = V _{f} - V _{i} = 6 - 4 = 2m/s\]

Shadow:

Yes, so what would our setup be for impulse?

zarkam21:

540*2

zarkam21:

j=540*2 j=1080

Shadow:

There you go

zarkam21:

the unit would be n right?

Shadow:

Use the units of mass times velocity (kg times m/s)

zarkam21:

so 1080 kg m/s

Shadow:

Yes

zarkam21:

=) Thank you so much

Shadow:

No problem

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