The number of unshelled peanuts in a 1 lb container is normally distributed with a mean of 375 peanuts and a standard deviation of 24 peanuts.

Suppose 4000 different 1 lb containers are in a warehouse.

About how many containers contain more than 447 peanuts?

Question

The number of unshelled peanuts in a 1 lb container is normally distributed with a mean of 375 peanuts and a standard deviation of 24 peanuts.

Suppose 4000 different 1 lb containers are in a warehouse.

About how many containers contain more than 447 peanuts?

Marziman · Answer

Hm, well determining the probability I'd say 6.

alis · Answer

okay, are you sure?

Marziman · Answer

Yes, is that an option?

Vocaloid · Answer

first step is to use the z-score formula to determine the z-score for 447 compared to the mean/standard deviation

z-score = (x - mean)/standard deviation

= (447-375)/24

then, once you have your z-score, you need to plug this into a z-score to percentile calculator and determine the percentage that this z-score corresponds to,

then calculate the number of containers by multiplying (percentage) * total # of containers