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Mathematics 8 Online
hardlyhuman:

@Shadow

hardlyhuman:

1 attachment
Shadow:

Area of a Rectangle: length times width Area of a Parallelogram: base times h

hardlyhuman:

the parallelogram is 12

hardlyhuman:

would the answer be 87?

Shadow:

Where'd you get that number from?

hardlyhuman:

1 attachment
Shadow:

So you used the hypotenuse of both triangles to solve for the length and width of the rectangle?

hardlyhuman:

yea

Shadow:

What did you get for them

hardlyhuman:

12

hardlyhuman:

and its a parallelogram

hardlyhuman:

i did it as parallelogram and rectangle

Shadow:

|dw:1519345996850:dw|

Shadow:

I got 3.60555127546 and 10.8166538264 for the hypotenuse.

Shadow:

Multiply those two, then add w/12

hardlyhuman:

okay im confused, i drew the two triangles to find the length and width of the rectangle and square thing, they arent part of the problem

Shadow:

Yeah, you draw the triangles to use Pythagoras theorem. Those lines are at a slope, so drawing a straight line and comparing it doesn't work.

hardlyhuman:

okay

hardlyhuman:

so was my answer right or no?

Shadow:

No

hardlyhuman:

dang it

hardlyhuman:

what did i do wrong

Shadow:

Say I have a crayon, and a pencil. I can slope the pencil so that it fits next to the crayon like so |dw:1519346460843:dw|

Shadow:

That crayon may be 5 inches, but the pencil is longer

Shadow:

You drew the crayon (9) up against the length of the rectangle (which is at a slope). That doesn't make the length of the rectangle 9

hardlyhuman:

okay, and i got 50.99999999998581

Shadow:

Hmm, round it to 51

hardlyhuman:

okay

hardlyhuman:

is that the answer?

Shadow:

Yes

hardlyhuman:

okay and is this one right

1 attachment
Shadow:

The answer to this one isn't 51. It's the answer to the previous one above. If you have another question, open up a new one.

hardlyhuman:

yeah i got that but thats what i got for that one

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