Question

Solve for f.

d = 16ef²

A. f = ± √de/4e

B. f = ± 4√de/e

C. f = ± 4√de

D. f = ± √de/16

Answer 1

@Vocaloid

Answer 2

try to think about what steps you need to take to isolate f

for example, since f is being multiplied by 16 and e what do you need to do to "undo" this?

Answer 3

well the answer is A correct ?

Answer 4

yeah that's it

Answer 5

Solve for e.

T = e^2/9

A. e = ± 3√T

​​B. e = ± 3√T/T

C.​ e = ± 9√T​

D. e = ±3T

Answer 6

any ideas?

Answer 7

the answer is C or B

Answer 8

the answer is B

Answer 9

T = e^2/9

start by multiplying both sides by 9, what do you get?

Answer 10

81

Answer 11

e^2/9 * 9 = ?

Answer 12

73

Answer 13

hint: notice how e^2 is being divided by 9 and then multiplied by 9 so they cancel out

Answer 14

ok that's true

Answer 15

so e^2 / 9 * 9 = e^2

e^2 = 9T

solve for e

Answer 16

= 0

Answer 17

i'm still working on my calculations

Answer 18

hint: you have e^2 on one side so simply take the square root of both sides to isolate e

e = sqrt(9T) and then simplify until it looks like one of the answer choices

Answer 19

T = e/9

Answer 20

what's the square root of 9?

Answer 21

3

Answer 22

OH I see

Answer 23

good, so sqrt(9T) = +/- 3sqrt(T) answer choice A

Answer 24

it's A

Answer 25

yes

Answer 26

The formula represents the distance x traveled by an object with acceleration a for t seconds.

x = 1/2at^2

Solve for t.

A. t = ±√x/2a

B. t = ± 2ax^2

C. t = ± √2xa/a

D. t = ± 1/2√ax

Answer 27

THE ANSWER IS C

Answer 28

yeah good

Answer 29

The formula gives the volume V of a right cylinder with radius r and height h.

V=πr^2h

Solve for r.

A. r = √Vπh

B. r = π√Vh

C. r = √Vπh/h

D. r = √Vπh/πh

Answer 30

THE ANSWER IS D

Answer 31

good

Answer 32

Solve for t.

d = −16t^2 + 8t

A. t = 1/4 ± 8√1 − d​

B. t = 8 ± √1 − d

C. t = 1/2 ± 8√1 − d

D. t = 1/4 ± √1−d/4

Answer 33

The Answer is D

Answer 34

is it correct cause i'm not sure

Answer 35

good

Answer 36

D is correct ?

Answer 37

yes

Answer 38

thank you Vocaloid once again for your help