https://static.k12.com/nextgen_media/assets/8118131-NP100_501_01.jpg In the diagram, the radius of the outer circle is 2x cm and the radius of the inside circle is 6 cm. The area of the shaded region is 288π cm^2. What is the value of x? Enter your answer in the box. x = ______ cm
@Vocaloid
the answer is 12
Please check your calculations again
pi(2x)^2 - pi(6)^2 = 288 start by adding pi(6)^2 to each side
36pi
pi(2x)^2 = 288 + pi(6)^2 then divide both sides by pi
5.64962935 , − 5.64962935
0
please follow my instructions if something is unclear I am ok with you asking me to explain something in more detail pi(2x)^2 = 288 + pi(6)^2 divide by pi to get (2x)^2 = (288 + pi(6)^2)/pi
then, take the square root of both sides
my calculations might be wrong but i'm still working on it
2x = sqrt((288 + pi(6)^2)/pi)) then divide by 2 to get x, keep in mind this is the radius of a circle so the distance must be positive
now i figured it out If we increase both dimensions by x then: (x+9)(x+13) = 192 x2 + 22x + 117 = 192 x2 + 22x - 75 = 0 (x+25)(x-3) = 0 x = -25 or x=3
Discarding the negative, we increase both dimensions by 3 The larger dimensions are 16 m by 12 m
@Vocaloid
that is completely irrelevant to the problem we are solving
x = sqrt((288 + pi(6)^2)/pi))/2 = ?
6
am i correct ?
no x = sqrt((288 + pi(6)^2)/pi))/2 = ?
63
you just need to plug this into a calculator
sqrt((288 + pi(6)^2)/pi))/2 = ?
5.64962935114
wait hold on
the area is 288 pi not 288 crap
sorry try this sqrt((288*pi + pi(6)^2)/pi))/2 = ?
9
good so x = 9 = your answer
is 9 is the length ?
i thought i was 16
where are you getting 16?
due to my calculations
If we increase both dimensions by x then: (x+9)(x+13) = 192 x2 + 22x + 117 = 192 x2 + 22x - 75 = 0 (x+25)(x-3) = 0 x = -25 or x=3
you copy-pasted something from a completely different problem
again, that is completely irrelevant to this problem
no it's from this problem that i figured out
pi(2x)^2 - pi(6)^2 = 288 ^ these numbers come from the problem (x+9)(x+13) = 192 ^ these numbers are not part of this problem
ok i see
so your answer is 9, everything else you have pasted is from a different problem
The height of a triangle is 5 m less than its base. The area of the triangle is 42 m². What is the length of the base? Enter your answer in the box. _____ m
now the answer is 12 m
this was easy
good, 12.
wait a minute wait a minute i'm sorry you were right
i was tripping on another problem
Ted throws an object straight up into the air with an initial velocity of 54 ft/s from a platform that is 40 ft above the ground. Use the formula h(t) = −16t^2 + v0t + h0 , where v0 is the initial velocity and h0 is the initial height. How long will it take for the object to hit the ground? A. 1 s B. 2 s C. 3 s D. 4 s
THE ANSWER IS D
you are given: −16t^2 + v0t + h0 you are also given v0 as the initial velocity 54 and h0 as the initial height 40 so -16t^2 + (54t) + 40 "hits the ground" means height = 0 so -16t^2 + (54t) + 40 = 0 solve for t would recommend factoring the 4 out then using the quadratic formula
good, D is right
Adina has a rectangular garden that measures 9 m wide by 13 m long. She wants to increase the area to 192 m² by increasing the width and length by the same amount. What will be the length (longer dimension) of the new garden? Enter your answer in the box. ______ m
If we increase both dimensions by x then: (x+9)(x+13) = 192 x2 + 22x + 117 = 192 x2 + 22x - 75 = 0 (x+25)(x-3) = 0 x = -25 or x=3
that's what i meant
the answer is 16 my mistake i forgot to look at the question we were working at
yeah that's right, 16
Thank you for your help and do you forgive me ?
yeah, it's fine, don't worry about anything
ok thx
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