Question

Help

Answer 1

I'm leaning towards choice A

Answer 2

@Vocaloid Okay fine. :)

Answer 3

if you want to solve it i'm ok with that

Answer 4

No no no, all you birthday girl

Answer 5

so for this one it's kind of trial and error-ish, I'd start by trying to figure out what quadrant it needs to be in for opposite/hypotenuse to be negative, but adjacent/hypotenuse to be positive

Answer 6

hypotenuse is always positive, so we just need to consider the sign of cos and sin

if cos is positive, then the x-value should be positive, and if sin is negative, then we should expect the y value to be negative

so your intuition is correct, it ends up being q4

Answer 7

remember that sec = 1/cos, so cos = 3/5, with the terminal point being in quadrant 4, so try sketching this out and seeing which answer choices are mathematically valid

Answer 8

Um a

Answer 9

if my calculations are correct there are exactly 2 correct choices

Answer 10

and c

Answer 11

have to be careful with signs

Answer 12

since the 4 is below the x-axis it's -4 so tan(theta) would be -4/3

any other possibilities? as a hint, try calculating sin(theta)

Answer 13

D

Answer 14

the side lengths are 3, 4, and 5 so there's no way sign can be -2/5

Answer 15

sin(theta) = opposite/hypotenuse = ?

Answer 16

Its definitely a I'm stuck between b and c

Answer 17

the side "opposite" to the angle theta is -4

the hypotenuse is 5

so sin(theta) = ?

Answer 18

b

Answer 19

good, sin(theta) = -4/5 so csc(theta) = -5/4 so A + B = your ans

Answer 20

A

Answer 21

good

Answer 22

B

Answer 23

good

Answer 24

B

Answer 25

not quite, as a hint try sketching the triangle and calculating tan

Answer 26

opposite/adjacent = ?

*** make sure to consider negative signs

Answer 27

oh c

Answer 28

if opposite = -12 and adjacent = -5 what must tan be?

Answer 29

tan(theta) = opposite/adjacent = (-12/-5 ) = 12/5 making which answer choice the best possibility?

Answer 30

A

Answer 31

good

Answer 32

as a hint, sec(theta) = 1/cos(theta) so sec theta will be undefined whenever cos(theta) = 0

Answer 33

so a and c

Answer 34

you might be thinking of sin(theta) not cos(theta), cos(theta) is 0 on integer multiplies of (pi/2)

Answer 35

B

Answer 36

good, what else?

Answer 37

D

Answer 38

good so B + D = your ans

Answer 39

unit circle has radius 1

treat every coordinate as a set of x and y values and see whether x^2 + y^2 = 1 or not

Answer 40

D

Answer 41

good but there's one more

Answer 42

C

Answer 43

is (1/3)^2 + (2/3)^2 equal to 1?

Answer 44

no hold on

Answer 45

Ugh um a

Answer 46

actually no b

Answer 47

good, B + D

Answer 48

stuck ugh between b and d

Answer 49

try determining csc (theta) from this diagram

as a hint csc(theta) = 1/sin(theta)

Answer 50

so definitely b or d

Answer 51

sin(theta) = ? based on the diagram

Answer 52

as a reminder sin(theta) = opposite/hypotenuse = ?

Answer 53

D

Answer 54

good, D

Answer 55

A and d

Answer 56

not quite

as a hint, you can generate new reference angles by adding or subtracting 2pi

for a reference angle and all of its related angles, the trigonometric ratios should be the same

for example, A does not work because cos(pi/6) does not equal cos(8pi/6)

Answer 57

c and D :)

Answer 58

nvm yeah C + D is right

Answer 59

Yay thanks