What is the measure of AC ? https://static.k12.com/nextgen_media/assets/8095486-NG_GMT_DP024_298_004.jpg PLZZ HELP!
Not sure what the symbols after the AC are but the arc is double the measure of the inscribed angle So you would do \((2.5x+4)=2(7x-2)\) or you can do this \(\frac{(2.5x+4)}{2}=(7x-2)\) Which ever you feel more comfortable with
THnx u.
I mean this is not the answer you still have to solve for x, which one do you want to do?
ill do the first one.
Alright so we first have to distribute the 2 \((2.5x+4)=2(7x-2)\\ (2.5x+4)=14x-4\) Do you know what to do from here?
No i dont.
So we have to get the x's on one side and the non-x values on the other side \(2.5x+4=14x-4\) Lets add 4 to both sides \(2.5x+8=14x\) Then we subtract 2.5x from both sides \(8=11.5x\) Do you know what to do from here?
x=0.61?
You would divide by 11.5 on both sides. \(\frac{8}{11.5}=\frac{11.5x}{11.5}\\ \frac{8}{11.5}=x\\ or~x=0.69565\dots \)
ok thts what i got. thnx
Now we still aren't done, we are trying to find arc AC
what we have to do?
We have to substitute x back in for AC \(AC=(7x-2)\)
7(8/11.5)-2
Right
2.869565217
Right?
Yes or you can write \(\frac{33}{11.5}\) I don't know what specifically your teacher looks for (fraction or decimal)
its a percent.
Do you mean degrees?
yess thts what i mean.
Either are right, probably do the decimal
ok decimal how to put it as?
Probably round to the hundreths place \(\approx0.87\)
ok
Wait.
what happen?
\(\color{#0cbb34}{\text{Originally Posted by}}\) @dude Alright so we first have to distribute the 2 \((2.5x+4)=2(7x-2)\\ (2.5x+4)=14x-4\) Do you know what to do from here? \(\color{#0cbb34}{\text{End of Quote}}\) Mistake here I wrote it incorrectly Should be \((2.5x+4)=\frac{(7x-2)}{2}\) :| Sorry about that that means that we didnt find the right answer
\(2.5x+4=\frac{(7x-2)}{2}\) Multiply both sides by 2 \(2(2.5x+4)=(7x-2)\\ 5x+8=7x-2\) Add 2 on both sides then subtract 5 on both sides \(10=2x\\ 5=x\)
Then we substitute back into AC \(AC=7x-2\\ =7(5)-2\\ =35-2\\ \boxed{AC=33}\) That was my mistake, very sorry
Oh ok i got i u now.
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