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Mathematics 15 Online
mplatt:

What is the measure of AC ? https://static.k12.com/nextgen_media/assets/8095486-NG_GMT_DP024_298_004.jpg PLZZ HELP!

dude:

Not sure what the symbols after the AC are but the arc is double the measure of the inscribed angle So you would do \((2.5x+4)=2(7x-2)\) or you can do this \(\frac{(2.5x+4)}{2}=(7x-2)\) Which ever you feel more comfortable with

mplatt:

THnx u.

dude:

I mean this is not the answer you still have to solve for x, which one do you want to do?

mplatt:

ill do the first one.

dude:

Alright so we first have to distribute the 2 \((2.5x+4)=2(7x-2)\\ (2.5x+4)=14x-4\) Do you know what to do from here?

mplatt:

No i dont.

dude:

So we have to get the x's on one side and the non-x values on the other side \(2.5x+4=14x-4\) Lets add 4 to both sides \(2.5x+8=14x\) Then we subtract 2.5x from both sides \(8=11.5x\) Do you know what to do from here?

mplatt:

x=0.61?

dude:

You would divide by 11.5 on both sides. \(\frac{8}{11.5}=\frac{11.5x}{11.5}\\ \frac{8}{11.5}=x\\ or~x=0.69565\dots \)

mplatt:

ok thts what i got. thnx

dude:

Now we still aren't done, we are trying to find arc AC

mplatt:

what we have to do?

dude:

We have to substitute x back in for AC \(AC=(7x-2)\)

mplatt:

7(8/11.5)-2

dude:

Right

mplatt:

2.869565217

mplatt:

Right?

dude:

Yes or you can write \(\frac{33}{11.5}\) I don't know what specifically your teacher looks for (fraction or decimal)

mplatt:

its a percent.

dude:

Do you mean degrees?

mplatt:

yess thts what i mean.

dude:

Either are right, probably do the decimal

mplatt:

ok decimal how to put it as?

dude:

Probably round to the hundreths place \(\approx0.87\)

mplatt:

ok

dude:

Wait.

mplatt:

what happen?

dude:

\(\color{#0cbb34}{\text{Originally Posted by}}\) @dude Alright so we first have to distribute the 2 \((2.5x+4)=2(7x-2)\\ (2.5x+4)=14x-4\) Do you know what to do from here? \(\color{#0cbb34}{\text{End of Quote}}\) Mistake here I wrote it incorrectly Should be \((2.5x+4)=\frac{(7x-2)}{2}\) :| Sorry about that that means that we didnt find the right answer

dude:

\(2.5x+4=\frac{(7x-2)}{2}\) Multiply both sides by 2 \(2(2.5x+4)=(7x-2)\\ 5x+8=7x-2\) Add 2 on both sides then subtract 5 on both sides \(10=2x\\ 5=x\)

dude:

Then we substitute back into AC \(AC=7x-2\\ =7(5)-2\\ =35-2\\ \boxed{AC=33}\) That was my mistake, very sorry

mplatt:

Oh ok i got i u now.

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