Question

help please

Answer 1

\[f(x) = 4x^2 + 19x - 5\]
\[g(x) = 4x^2 - x\]

\[\frac{ f }{ g }(x) = \frac{ 4x^2 + 19x - 5 }{ 4x^2 - x }\]

Answer 2

\[\frac{ f }{ g }(x) = \frac{ (4x -1)(x + 5) }{ x(4x - 1) }\]

Cross out (4x - 1) in the numerator and (4x - 1) in the denominator

\[\frac{ f }{ g }(x) = \frac{ (x + 5) }{ x }\]

Answer 3

@princeevee Are you there?

Answer 4

yeah

Answer 5

What do you think the answer is?

Answer 6

i would think either B or D

Answer 7

But we got

\[\frac{ (x + 5) }{ x }\]

Answer 8

Did you look at the work i did ._.

Answer 9

yeah.