Can someone help me in math? Thank you
The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass. Starting with 155 grams of a radioactive isotope, how much will be left after 6 half-lives?
Round your answer to the nearest gram.
Using the half life formula: Nn=No(1/2)n, where Nn = quantity remaining after n half-lifes, and No = initial quantity Nn=(150)(1/2)6 = 150(1/64) = 2.34g
Damn im far off lol
the above answer is not correct because the initial amount is 155 not 150g
I got 20...
|dw:1520958726971:dw|
initial amount is 155, t/h would be 6 since you have 6 half lives so A = 155(1/2)^6 = ?
._.
you just need to plug it into a calculator.
1/2^6 goes first right?
(1/2)^6, yes, parentheses are important here
0.015625
yup then just multiply that by 155
Now I multiply that by 155?
Oh alright :)
2.421875
awesome, since we were given 155 which has 3 significant figures we round that to 3 sig figs getting 2.42g = your answer
...
You totally lost me in the "sig figs"... your explanation went Chinese at that point ._.
if you haven't learned about significant figures yet don't worry about it
I believe the answer is 20? correct
@Vocaloid
Hey sexy lady -points at Voca & Sup-
Opa Opa Opa Gangname style c;'
...
where are you getting 20? we established that the answer was 2.42g
Im a guy bruh
~(._.~)
Please don't derail the topic
^^^
(~._.)~ ~(._.)~ K, i'm done
Well...
Because I put 20 as the answer and it said it was right...
¯\_(ツ)_/¯ Math nowadays... never to be understood by humanity Mental Abuse To Humans
she ignored it lmao
Oh don't worry Voca... I know you are very smart ^.^ just sometimes these dumb systems don't even know the answers and expect humans to know it
lol
Welp off to my next question
#SemperFi
Join our real-time social learning platform and learn together with your friends!