8bithelix:

gonna need math help and tons http://prntscr.com/iugyez

8 months ago
Vocaloid:

so we're going to have to complete the square, any ideas on how to get started?

8 months ago
Vocaloid:

well, let's start with our function f(x) = x^2 + 8x + 13 we'll have to re-write this so it's a perfect square trinomial let's box this part in parentheses first f(x) = (x^2 + 8x) + 13 to turn the part inside the parentheses into a perfect square, we take the middle coefficient (the coefficient of x), divide by 2, then square it, lmk what you get

8 months ago
8bithelix:

next question

8 months ago
8bithelix:

i really just need help on how to graph this

8 months ago
8bithelix:

http://prntscr.com/iuhzik

8 months ago
8bithelix:

dont mind that side note in the question lol

8 months ago
Vocaloid:

well, a good start would be plotting the axis of symmetry, vertex, and y-intercept, then you treat the axis of symmetry as a "mirror" and draw two equal halves of the parabola it's probably easier to show than say it with words, just a moment

8 months ago
Vocaloid:

|dw:1521664724024:dw|

8 months ago
Vocaloid:

|dw:1521664787134:dw|

8 months ago
Vocaloid:

|dw:1521664810567:dw|

8 months ago
8bithelix:

ah ok

8 months ago
Vocaloid:

then, we "mirror" across the other side you can plug a few more x-values into the equation if you want to make the graph a little more accurate

8 months ago
Vocaloid:

|dw:1521664850155:dw|

8 months ago
Vocaloid:

something like that

8 months ago
Vocaloid:

it's not explicitly asked for but finding the x-intercepts could help make the graph a little more accurate

8 months ago
8bithelix:

http://prntscr.com/iuiwwv

8 months ago