PLS HELP!!! QS is the perpendicular bisector of PR . Solve for x. https://dlap.gradpoint.com/Resz/~yUA6AAAAAAQzi_EEDSiPwA.-c1n8jFGR2INWft2KDocAD/7234256,F04/Assets/questions/quiz/geometry/geoconst/geoconst-g-17.png
Well? What's the relationship between PS and SR?
they're collinear?
They're the same. QS bisects PR, which means PS and SR must be the same. Based on that, what can we do to solve for 'x'?
green, are you good at geometry/cal?
I don't get it
do we need to make them equal, and solve?
QS bisects PR. That means that PS and SR have to be equal to each other, since bisect means to divide equally in half. PS is 2x - 20 SR is 70 - x We can set these two equal to each other.
@BenLindquist Uh, what's your problem? It's been a year since I've taken Calculus, dunno how much of it I'd remember.
I might need help with geometry mostly. I have cal as an elective
It all depends on the question.
Anyway, @eviant can you set those two equal to each other and solve?
50?
is what i came up with
Not quite, try again. You can do it step-by-step here if you want.
I have to subtract 20 from both sides
Wait no, it's being subtracted. So we have to do the opposite.
so, add
\(\sf 2x - 20 = 70 - x\) Yes
What are you left with?
so, it'd be 2x-40=70-20x?
What? No...add 20 to both sides: \(\sf 2x-20\color{red}{+20}=70-x\color{red}{+20}\)
now, subtract,?
or divide?
Simplify it... -20 + 20 = ? 70 + 20 = ?
90
and 0
Yes..so we're left with: \(\sf 2x=90-x\) Now what do we do?
divide, so the answer is 45?
No, we still have to get rid of that other 'x'...what do we do to it?
subtract it?
It's being subtracted from the 90. We have to do the opposite.
so, add it, 90+x
Add it to both sides. The whole point is to get rid of the 'x' on the right side. \(\sf 2x\color{red}{+x}=90-x\color{red}{+x}\)
2x + x = ? -x + x = ?
3x?
Yes, and...?
90 divide by 3=30?
so, 30 is the answer?
Yep, you got it.
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