Question

Part I :
Part II : None
Part III : 1/2
Part IV : 2pi

Answer 1

for part I: the negative sign is on the outside of the function
does that reflect across y-axis or across x-axis?

Answer 2

y

Answer 3

not quite, the negative sign outside reflects across the x-axis

so the sol'n would be something like "reflects across the x-axis"

Answer 4

y-axis would have to be tan(-x)

Answer 5

for part II) the entire function is being multiplied by 3 so that's the vertical stretch factor

Answer 6

for part III) horizontal stretch factors stretch the function by 1/a not a, so it's the reciprocal of 1/2 which is...?

Answer 7

okay so for part 2 is it 3

Answer 8

PArt II 3
PArt III 2

Answer 9

wait wait wait

Answer 10

this is a tan function so yeah you're right it's 2pi

Answer 11

so yeah part IV is 2pi

Answer 12

Part I: What kind of reflection does the basic function experience? (2 points)


reflects across the x-axis


Part II: What is the vertical stretch factor of the function R(x)? (2 points)

3

Part III: What is the horizontal stretch factor of the function R(x)? (4 points)

2

Part IV: What is the period of the function R(x)? (4 points)

2pi

Answer 13

good

Answer 14

Part V : x=2pi n

Answer 15

hm. I know that's what mathway gives but it doesn't quite seem right to me

since tan(x/2) takes its asymptotes on odd multiplies of pi I'd write this as

2 * n * pi + pi

Answer 16

oh okay for part V?

Answer 17

part V I'd say 2pi*n + pi, part VI would be 2*pi*n since it takes its zeros on even values of pi

Answer 18

this for the graph

Answer 19

good

since the graph in the problem uses radians on its x tick-marks instead of integers, I would recommend sketching where the asymptotes are (odd multiples of pi) and using that to guide your sketch

Answer 20

Got it, thank you so much !!