Event A has a 0.3 probability of occuring and event B has a 0.4 probability of occuring. A and B are independent events. What is the probability that neither A or B occurs?

Question

Vocaloid · Answer

I'm not 100% sure on this but

probability that neither A nor B occurs = 1 - probability that A only occurs - probability that B only occurs - probability that A and B occur

probability that A and B occur = P(A) * P(B)

the other probabilities are given in the problem, simply plug everything into the first equation to solve

ratnakermehta20 · Answer

$$P(A)=0.3, P(B)=0.4.$$
Recall that, if A and B are independent, then, so are A' and B'.
Hence, the required prob. is $$P(A'^B')=P(A')*P(B')=[1-P(A)][1-P(B)]=(0.7)(0.6)=0.42.$$