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Mathematics 15 Online
kaylak:

help @vocaloid

kaylak:

1 attachment
kaylak:

1 is a

kaylak:

2 is b

kaylak:

3 is d

kaylak:

4 is c

Vocaloid:

check # 2 again, you made a sign error

kaylak:

2 is d

Vocaloid:

good, and the other ones 1,3, 4 are correct

kaylak:

1 attachment
Vocaloid:

|dw:1522774230168:dw|

Vocaloid:

so you'll need to find: the dot product, the magnitudes of u and v, and plug them into equation 3 to find theta

kaylak:

2 is a

kaylak:

@Vocaloid

Vocaloid:

good

Vocaloid:

for 3) calculate the vector for the displacement by subtracting final distance vector - intial vector, then find the dot product of force and displacement

kaylak:

1 c?

kaylak:

@Vocaloid

Vocaloid:

hold on I just need to re-do the calculations b/c I'm getting a weird # :S

kaylak:

c for 3 maybe need to do problem

kaylak:

redo

Vocaloid:

alright, for #1: let's start from the top, what did you get for the dot product

kaylak:

-12 -16

Vocaloid:

good, so when you add those together you get -12 - 16 = -28 what about the magnitudes of u and v?

kaylak:

so I'm squaring again right?

Vocaloid:

magnitude = r = sqrt(x^2+y^2) calculate the magnitudes of u and v

kaylak:

is the answer a

Vocaloid:

please follow my instructions

kaylak:

ok so 20

Vocaloid:

check your calculations again the vector u has x-coordinate -2 and y-coordinate 8 plug these into the magnitude formula to find the magnitude of u.

kaylak:

7.7

Vocaloid:

good but we can leave it in radical form until the end, so sqrt(68) repeat the same thing with the coordinates of v

kaylak:

5.7

kaylak:

or leave it in radical form

Vocaloid:

yeah we can just leave it in radical form so we don't lose accuracy until the every end so cos(theta) = -28/sqrt(68*40), solve for theta

kaylak:

It's d then

kaylak:

@Vocaloid

Vocaloid:

good

kaylak:

3 c/

Vocaloid:

good, 3 = C

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