Question

If 1.85 g of Mg(OH)2 reacts with 3.71 g of HCl,
how much MgCl2 is produced? What is the limiting
reactant?
__ Mg(OH)2 + __ HCl __ MgCl2 + __ H2O

Answer 1

meant to get to this earlier but

first you would start off by balancing all the coefficients in the equation such that each element is represented in equal moles on each side

then, you will convert 1.85 g of Mg(OH)2 to moles and 3.71g of HCl to moles, then judge by the coefficients of the equation to see which one will create less product (the reactant that creates less product is your limiting reactant)

then you will use the limiting reactant to calculate how much MgCl2 is produced

lmk if you need assistance with any of these steps