Question

Draw the electric field lines around a positive charge.

Answer 1

good, it would look something like that

Answer 2

Calculate the electric force that exists between two objects that are 0.500 m apart and carry charges of 0.00450 C and 0.00240 C. Is this force attractive or repulsive?

Answer 3

F = kqq/r^2

Answer 4

F=0.500*0.500(0.00450)

Answer 5

1. you must include the value of k (8.99*10^9)
2. q represents the charges, r represents the distance

Answer 6

F=(8.99*10^9)(0.00450)(0.00240)/0.500^2
F=388368

Answer 7

good

units of force are newtons (N) as usual

if the two charges are both positive is it the force attractive or repulsive?

Answer 8

repulsive

Answer 9

good, that's it

Answer 10

c. How does the size of the electric force between two charged objects change if the amount of charge on one of the objects is doubled? (2 points)



d. How does the size of the electric force between two charged objects change if the charges are moved farther apart? (1 point)

Answer 11

well we did a similar problem like this, what would the effect be for c) if we double one of the charges?

Answer 12

well it would be doubled

Answer 13

*2

Answer 14

good

for d) if the distance between the charges increases what happens to the force?

Answer 15

if the distance increases does the force increase or decrease?

Answer 16

decrease

Answer 17

it is the inverse

Answer 18

good, that's it

Answer 19

well it looks like there's about an equal # of positive and negative charges so would the overall charge be positive/negative/or neutral?

Answer 20

neutral

Answer 21

good

then for f, since there's a negative rod, you would expect the positive charges within the sphere to be drawn towards the rod while the negative ones are distributed on the other side, try sketching this

Answer 22

other way around, the negative charges are away from the rod and the positive ones are going towards the rod

Answer 23

good

Answer 24

I'd probably move some of those positive charges up a bit so it's closer to the rod

Answer 25

the rod is on the upper right corner so that's where the positive charges need to be

Answer 26

if you have a "rotate" tool you could rotate the circle a little bit counter clockwise

Answer 27

yeah that's probably fine