Question

Helpp please

Answer 1

a) capacitance = Q/V

Answer 2

20.0/3.40*10^-10
=

Answer 3

other way around, you put voltage on top instead of charge

Answer 4

0.00000

Answer 5

(3.4*10^(-10))/20 = ?

Answer 6

try wolframalpha, mathway isn't giving enough precision

Answer 7

1.7*10^-11

Answer 8

good, units on capacitance are farads as usual

Answer 9

b)

anyway, when two negative charges are close together, do you think the potential energy increases or decreases?

Answer 10

hint: consider the equation U = kqq/r

Answer 11

descreases

Answer 12

well, when r is very small, is the value of kqq/r very large or very small?

Answer 13

like, is 100/0.00001 a very large or a very small number?

Answer 14

large

Answer 15

good, so when r is very small and the charges are brought close together, the potential energy increases, which means the kinetic energy must decrease since total energy is constant

^ should be sufficient for b

Answer 16

anyway c is a similar calculation as part a), C = Q/V

Answer 17

(4.0*10^(-10))/25

1.6*10^-11 farads

Answer 18

good