Precalculus
Hm?
If \[\tan (\frac{ \pi }{ 3 } - A) = \cot (\frac{ \pi }{ 3 })\] What is A? \[0 < A < \frac{ \pi }{ 2 }\]
Well, A is bigger then 0 and Smaller then Pie/2 right?
Than*
Yes, this has to do with Cofunction Identities.
Okay, So the pie is 3.14/2
That just means A is within the first quadrant of the unit circle
@bm717
Yes?
Sarah :)
Shadow :)
You know this question?
You have to isolate the function and take the inverse
\[\cot \frac{ \pi }{ 3 } = \frac{ \sqrt3 }{ 3 }\] \[\tan \frac{ \pi }{ 3 } - A = \frac{ \sqrt 3 }{ 3}\] \[\frac{ \pi }{ 3 } - A = \frac{ \pi }{ 6 }\] \[-A = - \frac{ \pi }{ 6 }\] \[A = \frac{ \pi }{ 6 }\]
Good?
Yeh, I think so.
I’m on mobile but the work is right... I believe.
You're great. I don't have $200 for you, so I hope my thanks can suffice.
LMAO I’ll be sending the bill to you in.a little bit.
Wow
It might take a while however, knowing you live on el Hawaii
I'll find a way to pay you back
You better.
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