Question

An expression is shown below:

3pf2 − 21p2f + 6pf − 42p2

Part A: Rewrite the expression so the GCF is factored completely. (4 points)

Part B: Rewrite the expression completely factored. Show the steps of your work. (6 points)

Answer 1

\[3pf^2-21p^2f+6pf-42p^2\]

Answer 2

Are you solving it, or am I?

Answer 3

i need help solving it i was just making the equation easier to read

Answer 4

So, do you have any idea how to do this?

Answer 5

@Shadow

Answer 6

3p (f-7p) (f+2) and the GCF is 3p

Answer 7

You can check your work by throwing that in wolfram and seeing if it comes out to the expression you started with. I’m on mobile so I can’t be of much help, sorry.

Answer 8

@Spectre

Answer 9

I got (3pf - 21p²)(f + 2)

Answer 10

hmmmmmmm

Answer 11

@Spectre can u help me im confused

Answer 12

3pf² - 21p²f + 6pf - 42p²
= 3pf² + 6pf - 21p²f - 42p²
= 3pf(f +2) - 21p²(f + 2)
= (3pf - 21p²)(f +0 2)

Answer: (3pf - 21p²)(f + 2)

Answer 13

so if ^^^^ is part a what would part B be

Answer 14

so do this

Part A: (3pf - 21p²)(f + 2)


Part B:
3pf² - 21p²f + 6pf - 42p²
= 3pf² + 6pf - 21p²f - 42p²
= 3pf(f +2) - 21p²(f + 2)
= (3pf - 21p²)(f +0 2)

Factored GCF: (3pf - 21p²)(f + 2)

Answer 15

Looks right to me

Answer 16

Yes.