Question

Solve the radical equation, check for extraneous solutions

Answer 1

\[(3n+2)^{1/3}+1=0\]
So far I got
\](3n+2)^{1/3}=-1\]

Answer 2

Oof...

Answer 3

\][(3n+2)^{1/3}=-1\]

Answer 4

UGHHHH

Answer 5

\[(3n+2)^{1/3}=-1\]

Answer 6

haha yup

Answer 7

what do you think should be the next step?

Answer 8

\[^{3}\]

Answer 9

yup!

Answer 10

\[(3n+2)=-3/]

Answer 11

hmm
(-1)^3 = (-1)*(-1)*(-1) = ?

Answer 12

I’m going to kill myself...
\[(3n+28=-3\]

Answer 13

Ooooof... so... -1?

Answer 14

haha yeah

Answer 15

Add 2?

Answer 16

3n + 2 = -1 so far right?

Answer 17

Yes, with “()” around 3n+2

Answer 18

ok so we want to solve for n

that means we should subtract 2 right?

Answer 19

Correct. So \[3n=-3\]
Or \[n=-1\]

Answer 20

perfect ^_^