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solve on the interval 0 2pi) 2secx+5=1
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Hello
You start by isolating x, as you would in algebra
\[2\sec x + 5 = 1\] \[2 \sec x = -4\] \[\sec x = -2\] Since: \[\sec = \frac{ 1 }{ \cos }\] We get: \[\frac{ 1 }{ \cos x} = -2\]
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\[1 = -2 \cos x\] \[\cos x = -\frac{ 1 }{ 2 }\]
@carson035
Do you know what you would do from here?
Cos of what angle = -1/2 Cosine refers to the x coordinate of an angle, and since this is negative, you want to look to the left side of the unit circle (quadrants 2 and 3)
Once you do that, the answer is pretty simple to find
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\[x = \frac{ 2 \pi }{ 3 }, \frac{ 4 \pi }{ 3 }\]
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@carson035
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