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Mathematics 25 Online
EndersWorld:

Factoring...

EndersWorld:

\[x^2-6x+8\]

Hero:

@EndersWorld take your best shot at it.

EndersWorld:

Okay. Gimme a few.

EndersWorld:

a=1 b=-6 c=8

EndersWorld:

ac=8

EndersWorld:

-2-4=-6 -2*-4=8

EndersWorld:

\[x^2-(2+4)x+8\]

EndersWorld:

\[x^2-2x-4x+8\]

EndersWorld:

\[x(x-2)-4(x-2)\]

Hero:

Great work so far.

EndersWorld:

\[(x-2)(x-4)\]

EndersWorld:

I can’t remember if that’s its or not...

Flamo:

The Disburtitive Property?

Hero:

If I were you though, I would try my best to avoid as much as possible using negative numbers for m and n. Instead do this: \(m + n = |b|\) \(m \times n = ac\)

EndersWorld:

Factoring.

Hero:

That way you don't get hung up on the negative numbers.

Hero:

You factored correctly though.

EndersWorld:

Okay... good... I found a trick,

Hero:

In this case, when finding \(m\) and \(n\) you should write: \(2 + 4 = 6\) \(2 \times 4 = 8\)

Hero:

When you do it this way, you know to substitute \(-6 = -(2 + 4)\) flawlessly with no confusion. But I think your confusion may be finally cleared up. I told you that you would get this eventually. Congrats.

EndersWorld:

Two shots of fireball helped.

Hero:

Two `shots` of `fireball`???

Flamo:

...

EndersWorld:

Cinnamon whiskey.

Hero:

Cinnamon Whiskey? How old are you?

EndersWorld:

Not old enough. Moving on.

Flamo:

You shouldn't do that.

Flamo:

Never Drink or do Drugs. They will kill You.

Flamo:

Slowly

Flamo:

..

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